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sleet_krkn [62]
3 years ago
15

Can someone please help, ty!! Will mark brainliest.

Physics
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

#1 ( Balanced ) ( Rest)

#2 ( Unbalanced)  ( Accelerating)

Explanation:

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Immunization, or immunisation, is the process by which an individual's immune system becomes fortified against an infectious agent.

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4 0
3 years ago
a sydiver jumps out of a plane. She fall dowward at a very fast speed. Which force is acting upon it?
UNO [17]

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6 0
3 years ago
What is the amount of charge a capacitor can store per volt of potential difference?
sladkih [1.3K]

The amount of charge a capacitor can store per volt of potential difference is called the capacitance of the capacitor.

<h3>What is the capacitance?</h3>

The capacitance has to do with the amount of charge that is stored by a capacitor. We know that a capacitor is a device that can be used to store electric charges. We have in it, two capacitors separated by a dielectric material.

Hence, the amount of charge a capacitor can store per volt of potential difference is called the capacitance of the capacitor.

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2 years ago
Read 2 more answers
Based on the law of conservation of energy, which statement is correct?
Nitella [24]

Answer:

You kinda left out the options you want us to choose from.

Resend the question with Full details

4 0
3 years ago
Four traveling waves are described by the following equations, where all quantities are measured in SI units and y represents th
agasfer [191]

Answer:

T_1=T_3=\dfrac{2\pi}{21}

T_2=T_4=\dfrac{2\pi}{42}

Explanation:

Wave 1, y_1=0.12\ cos(3x-21t)

Wave 2, y_2=0.15\ sin(6x+42t)

Wave 3, y_3=0.13\ cos(6x+21t)

Wave 4, y_4=-0.27\ sin(3x-42t)

The general equation of travelling wave is given by :

y=A\ cos(kx\pm \omega t)

The value of \omega will remain the same if we take phase difference into account.

For first wave,

\omega_1=21

\dfrac{2\pi }{T_1}=21

T_1=\dfrac{2\pi}{21}

For second wave,

\omega_2=42

\dfrac{2\pi }{T_2}=42

T_2=\dfrac{2\pi}{42}

For the third wave,

\omega_3=21

\dfrac{2\pi }{T_3}=21

T_3=\dfrac{2\pi}{21}

For the fourth wave,

\omega_4=42

\dfrac{2\pi }{T_4}=42

T_4=\dfrac{2\pi}{42}

It is clear from above calculations that waves 1 and 3 have same time period. Also, wave 2 and 4 have same time period. Hence, this is the required solution.

3 0
3 years ago
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