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trasher [3.6K]
3 years ago
9

Your empty hand is not hurt when it bangs lightly against a wall. Why does your hand hurt when it bangs against the wall while c

arrying a heavy load? Which of Newton's laws is most applicable?​
Physics
1 answer:
trapecia [35]3 years ago
6 0
It does not hurt when an empty hangs lightly against a wall because the wall applies an
equal and opposite reaction force on you. In this case, Newton's third law is applicable.
Our hand hurts, when we are carrying a heavy load. This is because; the downward force acts or
our hand. This downward force depends on the weight of load. In this case, Newton's second law
is applicable.
Pls mark me brainliest answer
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If a mass of 76 kg acts downward 0.38 m from the axis of rotation on one end of a board and another force of 129 N also acts dow
Semenov [28]

Answer:

y = 2.196 m

Explanation:

Mass, m = 76 kg

distance from axis of rotation, x = 0.38 m

Second Force, F = 129 N

moment arm of the second force, y = ?

Now, equating moments for the equilibrium

So,

m g × x = F x y

76 x 0.38 x 9.81 = 129 x y

y = \dfrac{76\times 0.38\times 9.81}{129}

y = 2.196 m

Hence, the length of the moment arm is equal to 2.196 m.

6 0
3 years ago
Identify two forms of friction that <br> oppose the motion of a moving car
babymother [125]
Static friction opposes the movement of car from the state of rest.
Dynamic or kinetic friction opposes the movement of the car when car is running at any speed.


8 0
3 years ago
A star with the same mass and diameter as the sun rotates about a central axis with a period of about 24.0 days. Suppose that th
Mila [183]

Answer:

a)  w = 2.52 10⁷ rad / s, b)  K / K₀ = 1.19 10⁴

Explanation:

a) We can solve this exercise using the conservation of angular momentum.

Initial instant. Before collapse

         L₀ = I₀ w₀

Final moment. After the collapse

         L_f = I w

angular momentum is conserved

        L₀ = L_f

         I₀ w₀ = I w                 (1)

         

The moment of inertia of a sphere is

        I = 2/5 m r²

we take from the table the mass and diameter of the star

        m = 1,991 10³⁰ kg

        r₀ = 6.96 10⁸ m

        r = 6.37 10⁶ m

to find the angular velocity let's use

       w = L / T

where the length of a circle is

      L = 2π r

      T = 24 days (24 h / 1 day) (3600 s / 1h) = 2.0710⁶ s

we substitute

      w = 2π r / T

      wo = 2π 6.96 10⁸ / 2.07 10⁶

      wo = 2.1126 10³ rad / s

we substitute in equation 1

      w = \frac{I_o}{I}

      w = 2/5 mr₀² / 2/5 m r² w₀

      w = (\frac{r_o}{r}) ² wo

      w = (6.96 10⁸ / 6.37 10⁶) ² 2.1126 10³

      w = 2.52 10⁷ rad / s

b) the kinetic energy ratio

      K = ½ m w²

       K₀ = ½ m w₀²

       K = ½ m w²

       K / K₀ = (w / wo) ²

       K / K₀ = 2.52 10⁷ / 2.1126 10³

       K / K₀ = 1.19 10⁴

7 0
3 years ago
In March 1999 the Mars Global Surveyor (GS) entered its final orbit about Mars, sending data back to Earth. Assume a circular or
shusha [124]

Answer: 5.944\times 10^{23}\ kg

Explanation:

Given

Time period T=7.08\times 10^3\ s

Orbital speed v=3.40\times 10^3\ m/s

mass of GS m_{GS}=930\ kg

Radius of Mars r=3.43\times 10^6\ m

Consider the mass of mars is M

Here, Gravitational pull will provide the centripetal force

F_G=F_c

\dfrac{GMm_{GS}}{r^2}=\dfrac{m_{GS}v^2}{r}\\M=\dfrac{v^2\cdot r}{G}\\M=\dfrac{(3.43\times 10^3)^2\cdot 3.43\times 10^6}{6.67\times 10^{-11}}

M=5.944\times 10^{23}\ kg

5 0
3 years ago
Nerve impulses in a human body travel at a speed of about 100 m/s. Suppose a person accidentally steps barefoot on a pebble. Abo
PilotLPTM [1.2K]

Answer:

The time required by the impulse to travel from foot to brain equals 0.019 seconds

Explanation:

For uniform motion the distance, speed, time are related by the equation

Distance=Speed\times time

In our case since the person is 1.90 meters tall so the nerve impulse will have to cover a distance of 1.90 meters at a speed of 100 m/s.

Hence the time required for the impulse to travel from foot to the brain can be calculated as

time=\frac{Distance}{speed}\\\\\therefore time=\frac{1.90m}{100m/s}=0.019seconds

4 0
3 years ago
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