The relationship of the speed of sound, its frequency, and wavelength is the same as for all waves: vw = fλ, where vw is the speed of sound, f is its frequency, and λ is its wavelength. ... The frequency is the same as that of the source and is the number of waves that pass a point per unit time.
A skill set is explicitly taught or an activity is completed
Answer:
<h2>441 J</h2>
Explanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
From the question we have
PE = 30 × 9.8 × 1.5
We have the final answer as
<h3>441 J</h3>
Hope this helps you
Answer:
a). 1.218 m/s
b). R=2.8![^{-3}](https://tex.z-dn.net/?f=%5E%7B-3%7D)
Explanation:
![m_{bullet}=6.99g*\frac{1kg}{1000g}=6.99x10^{-3}kg](https://tex.z-dn.net/?f=m_%7Bbullet%7D%3D6.99g%2A%5Cfrac%7B1kg%7D%7B1000g%7D%3D6.99x10%5E%7B-3%7Dkg)
![v_{bullet}=341\frac{m}{s}](https://tex.z-dn.net/?f=v_%7Bbullet%7D%3D341%5Cfrac%7Bm%7D%7Bs%7D)
Momentum of the motion the first part of the motion have a momentum that is:
![P_{1}=m_{bullet}*v_{bullet}](https://tex.z-dn.net/?f=P_%7B1%7D%3Dm_%7Bbullet%7D%2Av_%7Bbullet%7D)
![P_{1}=6.99x10^{-3}kg*341\frac{m}{s} \\P_{1}=2.3529](https://tex.z-dn.net/?f=P_%7B1%7D%3D6.99x10%5E%7B-3%7Dkg%2A341%5Cfrac%7Bm%7D%7Bs%7D%20%5C%5CP_%7B1%7D%3D2.3529)
The final momentum is the motion before the action so:
a).
![P_{2}=m_{b1}*v_{fbullet}+(m_{b2}+m_{bullet})*v_{f}}](https://tex.z-dn.net/?f=P_%7B2%7D%3Dm_%7Bb1%7D%2Av_%7Bfbullet%7D%2B%28m_%7Bb2%7D%2Bm_%7Bbullet%7D%29%2Av_%7Bf%7D%7D)
![P_{2}=1.202 kg*0.554\frac{m}{s}+(1.523kg+6.99x10^{-3}kg)*v_{f}](https://tex.z-dn.net/?f=P_%7B2%7D%3D1.202%20kg%2A0.554%5Cfrac%7Bm%7D%7Bs%7D%2B%281.523kg%2B6.99x10%5E%7B-3%7Dkg%29%2Av_%7Bf%7D)
![P_{1}=P_{2}](https://tex.z-dn.net/?f=P_%7B1%7D%3DP_%7B2%7D)
![2.529=0.665+(1.5299)*v_{f}\\v_{f}=\frac{1.864}{1.5299}\\v_{f}=1.218 \frac{m}{s}](https://tex.z-dn.net/?f=2.529%3D0.665%2B%281.5299%29%2Av_%7Bf%7D%5C%5Cv_%7Bf%7D%3D%5Cfrac%7B1.864%7D%7B1.5299%7D%5C%5Cv_%7Bf%7D%3D1.218%20%5Cfrac%7Bm%7D%7Bs%7D)
b).
kinetic energy
![K=\frac{1}{2}*m*(v)^{2}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7D%2Am%2A%28v%29%5E%7B2%7D)
Kinetic energy after
![Ka=\frac{1}{2}*1.202*(0.554)^{2}+\frac{1}{2}*1.523*(1.218)^{2}\\Ka=1.142 J](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B1%7D%7B2%7D%2A1.202%2A%280.554%29%5E%7B2%7D%2B%5Cfrac%7B1%7D%7B2%7D%2A1.523%2A%281.218%29%5E%7B2%7D%5C%5CKa%3D1.142%20J)
Kinetic energy before
![Kb=\frac{1}{2}*mb*(vf)^{2}\\Kb=\frac{1}{2}*6.99x10^{-3}kg*(341)^{2}\\Kb=406.4J](https://tex.z-dn.net/?f=Kb%3D%5Cfrac%7B1%7D%7B2%7D%2Amb%2A%28vf%29%5E%7B2%7D%5C%5CKb%3D%5Cfrac%7B1%7D%7B2%7D%2A6.99x10%5E%7B-3%7Dkg%2A%28341%29%5E%7B2%7D%5C%5CKb%3D406.4J)
Ratio =![\frac{Ka}{Kb}](https://tex.z-dn.net/?f=%5Cfrac%7BKa%7D%7BKb%7D)
![R=\frac{1.14}{406.4}\\R=2.8x10^{-3}](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B1.14%7D%7B406.4%7D%5C%5CR%3D2.8x10%5E%7B-3%7D)
Answer:
Subduction, Trench, Mantle
Explanation: