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2 years ago

What force does it take to accelerate a 7.2 kg object 3.0 m/s^2.

Physics

1 answer:

grin007 [14]2 years ago

3 0

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 7.2 × 3 = 21.6

We have the final answer as

Hope this helps you

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If the work function of a material is such that red light of wavelength 700 nm just barely initiates the photoelectric effect, w

marishachu [46]

Answer:

2.13 x 10^-19 J or 0.53 eV

Explanation:

cut off wavelength, λo = 700 nm = 700 x 10^-9 m

λ = 400 nm = 400 x 10^-9 m

Use the energy equation

$E = \frac{h c}{\lambda _{o}}+K$

Where, K be the work function

$\frac{h c}{\lambda} = \frac{h c}{\lambda _{o}}+K$

$K =hc\left ( \frac{1}{\lambda } -\frac{1}{\lambda _{0}}\right )$

$K =6.63\times 10^{-34}\times 3\times 10^{8}\left ( \frac{1}{4\times 10^{-7} } -\frac{1}{7\times 10^{-7}}\right )$

K = 2.13 x 10^-19 J

K = 0.53 eV

3 0

3 years ago

Do action and reaction cancel each other out?

galben [10]

Answer:

Action and reaction forces don't cancel each other out because they act on separate objects. ... Action and reaction forces are always equal in magnitude, so it's not possible to exert more force on an object than it can exert back.

Explanation:

8 0

3 years ago

A sinusoidal wave on a string is described by the wave function

JulsSmile [24]

The frequency of the wave is approximately 25/π Hertz

<h3>Wave function</h3>

The standard wave function is expressed according to the equation

y = Asin(2πft+2πx/λ)

where

λ is the wave length

Given the equation below

y=0.15 sin (0.80x - 50t)

Since 50 = 2πf

For the frequency

2πf = 50

f = 50/2π

f = 25/π Hertz

Hence the frequency of the wave is approximately 25/π Hertz

Learn more on speed of the wave here: brainly.com/question/25847009

#SPJ4

6 0

2 years ago

PLEASE HELP! WILL GIVE BRAINLY Which of the four fundamental forces acts over very long distances but does

Sergeu [11.5K]

Answer:

Explanation:

just did it

6 0

3 years ago

Read 2 more answers

An α-particle has a charge of +2e and a mass of 6.64 × 10-27 kg. It is accelerated from rest through a potential difference that

zzz [600]

Answer with Explanation:

We are given that

Charge on alpha particle=q=2 e= $2\times 1.6\times 10^{-19} C$

1 e= $1.6\times 10^{-19} C$

Mass of alpha particle=m= $6.64\times 10^{-27} kg$

Potential difference,V= $1.97\times 10^6 V$

Magnetic field,B=3.49 T

a.Speed of alpha particle=v= $\sqrt{\frac{2 qV}{m}}$

By using the formula

$v=\sqrt{\frac{2\times 2\times 1.6\times 10^{-19}\times 1.97\times 10^6}{6.64\times 10^{-27}}$

$v=1.38\times 10^7 m/s$

b.Magnetic force,F $=qvB=2\times 1.6\times 10^{-19}\times 1.38\times 10^7\times 3.49=1.5\times 10^{-11} N$

F= $1.5\times 10^{-11} N$

c.Radius of circular path, r= $\frac{mv^2}{F}$

$r= \frac{6.64\times 10^{-27}\times (1.38\times 10^7)^2}{1.5\times 10^{-11}}$

r=0.084 m

5 0

3 years ago