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1 year ago

Use the structural formulas below to determine the number of unshared pairs at each designated atom.

Chemistry

1 answer:

Aleks04 [339]1 year ago

7 0

A bond is formed when electrons are shared between atoms.

<h3>What is the number of unshared pairs?</h3>

A bond is formed when electrons are shared between atoms. This is what we call a shared pair. A lone pair or unshared pair is one that is domiciled on only one of the atoms in the bond.

Let us now look at the molecule shown in image 1;

The number of unshared pairs in atom a is 0
The number of unshared pairs in atom b is 2
The number of unshared pairs in atom c is 0

Let us now look at the molecule shown in image 2;

The number of unshared pairs in atom a is 1
The number of unshared pairs in atom b is 2
The number of unshared pairs in atom c is 3

Learn more about unshared pair:brainly.com/question/22238351

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If you mix 50mL of 0.1 M TRIS acid with 60 mL of0.2 M<br> TRIS base, what will be the resulting pH?

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<u>Answer:</u> The pH of resulting solution is 8.7

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$

<u>For TRIS acid:</u>

Molarity of TRIS acid solution = 0.1 M

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Putting values in above equation, we get:

$0.1M=\frac{\text{Moles of TRIS acid}\times 1000}{50mL}\\\\\text{Moles of TRIS acid}=0.005mol$

<u>For TRIS base:</u>

Molarity of TRIS base solution = 0.2 M

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Putting values in above equation, we get:

$0.2M=\frac{\text{Moles of TRIS base}\times 1000}{60mL}\\\\\text{Moles of TRIS base}=0.012mol$

Volume of solution = 50 + 60 = 110 mL = 0.11 L (Conversion factor: 1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[salt]}{[acid]})$

$pH=pK_a+\log(\frac{[\text{TRIS base}]}{[\text{TRIS acid}]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of TRIS acid = 8.3

$[\text{TRIS acid}]=\frac{0.005}{0.11}$

$[\text{TRIS base}]=\frac{0.012}{0.11}$

pH = ?

Putting values in above equation, we get:

$pH=8.3+\log(\frac{0.012/0.11}{0.005/0.11})\\\\pH=8.7$

Hence, the pH of resulting solution is 8.7

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