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Dimas [21]
3 years ago
13

3.95 g of sugar (C6H12O6) is dissolved in water to make 158 mL of solution. Find the molarity.

Chemistry
1 answer:
12345 [234]3 years ago
8 0

Answer:

[C₆H₁₂O₆] = 0.139 M

Explanation:

Molarity si defined as a sort of concentration. It indicates the moles of solute that are contained in 1 L of solution.

We can also say, that molarity are the mmoles of solute contained in 1 mL of solution.

For this case, the solute is sugar (glucose). Let's determine M (mmol/mL)

(3.95 g . 1mol / 180g) . (1000 mmol / 1mol) / 158 mL

We determine moles, we convert them to mmoles, we divide by mL

M = 0.139 M

Moles = 3.95 g . 1mol / 180g → 0.0219 mol

We convert mL to L → 158 mL . 1L/1000mL = 0.158L

M = 0.0219 mol / 0.158L = 0.139 M

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Why it is important for humans to conserve freshwater?
aniked [119]

Answer:

Conserving water can help alleviate the effects of water shortages in any given community. Water use drains other resources. Using in-house water resources requires energy to deliver the water to your home. This energy-use increases when you use hot water since a lot of energy goes into heating.

Explanation:

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6 0
2 years ago
There is a small block A and a large block B. Block A is 25 grams. Block B is 25 Grams.If Block A is located on the Moon and Blo
a_sh-v [17]

Answer:

They have the same mass

Explanation:

The two blocks have the same mass. Mass is the quantity of matter contained in a substance. Therefore, the two bodies have the same mass.

The weight is a measure of mass and gravity. The gravity on earth differs from that on the moon. Therefore, the two bodies have different weights.

Their volume is also different since one body is larger than the other. Therefore, density which is the mass per unit volume will also differ.

8 0
3 years ago
Determine whether each description applies to electrophilic aromatic substitution or nucleophilic aromatic substitution.
Alborosie

Answer:

a. electrophilic aromatic substitution

b. nucleophilic aromatic substitution

c. nucleophilic aromatic substitution

d. electrophilic aromatic substitution

e. nucleophilic aromatic substitution

f. electrophilic aromatic substitution

Explanation:

Electrophilic aromatic substitution is a type of chemical reaction where a hydrogen atom or a functional group that is attached to the aromatic ring is replaced by an electrophile. Electrophilic aromatic substitutions can be classified into five classes: 1-Halogenation: is the replacement of one or more hydrogen (H) atoms in an organic compound by a halogen such as, for example, bromine (bromination), chlorine (chlorination), etc; 2- Nitration: the replacement of H with a nitrate group (NO2); 3-Sulfonation: the replacement of H with a bisulfite (SO3H); 4-Friedel-CraftsAlkylation: the replacement of H with an alkyl group (R), and 5-Friedel-Crafts Acylation: the replacement of H with an acyl group (RCO). For example, the Benzene undergoes electrophilic substitution to produce a wide range of chemical compounds (chlorobenzene, nitrobenzene, benzene sulfonic acid, etc).

A nucleophilic aromatic substitution is a type of chemical reaction where an electron-rich nucleophile displaces a leaving group (for example, a halide on the aromatic ring). There are six types of nucleophilic substitution mechanisms: 1-the SNAr (addition-elimination) mechanism, whose name is due to the Hughes-Ingold symbol ''SN' and a unimolecular mechanism; 2-the SN1 reaction that produces diazonium salts 3-the benzyne mechanism that produce highly reactive species (including benzyne) derived from the aromatic ring by the replacement of two substituents; 4-the free radical SRN1 mechanism where a substituent on the aromatic ring is displaced by a nucleophile with the formation of intermediary free radical species; 5-the ANRORC (Addition of the Nucleophile, Ring Opening, and Ring Closure) mechanism, involved in reactions of metal amide nucleophiles and substituted pyrimidines; and 6-the Vicarious nucleophilic substitution, where a nucleophile displaces an H atom on the aromatic ring but without leaving groups (such as, for example, halogen substituents).

3 0
3 years ago
Solve for the volume of a 1.5x10^6cm^3 object in units of liters
Lunna [17]

Answer:

1000cm³=1litre

1.5x10^6cm^3=1.5x10^6cm^3/1000litre=1.5×1000000/1000=1.5×1000=1500litres.

6 0
3 years ago
Cacl2+2AgNO3(aq)-> Ca(No3)2 (aq)+2AgCl (s) if 25.0mL of a 2.00 m CaCl2 solution is used for the reaction shown above how many
antiseptic1488 [7]

Answer:

n_{Cl^-}=0.1molCl^-

Explanation:

Hello,

In this case, given the 2.00 M solution, we can compute the moles of calcium chloride that reacted:

n_{CaCl_2}=2.00\frac{mol}{L} *25.0mL*\frac{1L}{1000mL}=0.05molCaCl_2

Then, since in one mole of calcium chloride, we find two moles of chloride ions (see subscript), we can compute the moles of chloride ions that were involved in the reaction as shown below:

n_{Cl^-}=0.05molCaCl_2*\frac{2molCl^-}{1molCaCl_2}\\ \\n_{Cl^-}=0.1molCl^-

Best regards.

4 0
3 years ago
Read 2 more answers
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