The position of the particle is given by:
x(t) = t³ - 12t² + 21t - 9
Differentiate x(t) with respect to t to find the velocity x'(t):
x'(t) = 3t² - 24t + 21
Differentiate x'(t) with respect to t to find the acceleration x''(t):
x''(t) = 6t - 24
Answer:
3.85*10^8m
Explanation:
We know that
Speed v = distance/time t
So distance = v x t
So = 3*10^8 x 2.56s
= distatance = 7.7*10^8m
However this is double the distance from the earth to the moon, so to get distance from earth to the moon we divide by 2
7.7*10^8/2= 3.85*10^8m
Answer:
Wave A
<em>I</em><em> </em><em>hope this</em><em> </em><em>helps</em><em> </em>
Answer:
The magnitude of F₁ is 3.7 times of F₂
Explanation:
Given that,
Time = 10 sec
Speed = 3.0 km/h
Speed of second tugboat = 11 km/h
We need to calculate the speed


The force F₁is constant acceleration is also a constant.

We need to calculate the acceleration
Using formula of acceleration



Similarly,

For total force,


The speed of second tugboat is


We need to calculate total acceleration



We need to calculate the acceleration a₂



We need to calculate the factor of F₁ and F₂
Dividing force F₁ by F₂



Hence, The magnitude of F₁ is 3.7 times of F₂
I believe that the answer to the question provided above are the following;
x = 29.8410
y = 16.6794
z = -1.2642
Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.