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3 years ago

When the mass of the sun is larger, Earth moves around the sun at a faster or slower pace.

1 answer:

4 0

-- The mass of the sun never increases.

-- It does decrease, but not nearly enough to have any noticeable
effect on the orbital motion of the Earth, or any other planet.

-- When Earth is closer to the sun, it moves faster in its orbit.

-- When Earth is farther from the sun, it moves slower in its orbit.

-- The result is that the line from the sun to the Earth always covers
the same amount of area in the same length of time.

-- Johannes Kepler noticed this, and it's his Second Law of planetary motion.

-- Newton showed that if his equations for gravity and motion are correct,
then planets MUST behave this way.

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ser-zykov [4K]

The correct answer is B.Antartica and Australia were one landmass millions of years ago.

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3 years ago

What two factors will most likely change the speed of a mechanical wave?

iVinArrow [24]

Period and wavelength

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3 years ago

a whistle you use to call your hunting dog has a frequency of 21 khz, but your dog is ignoring it. you suspect the whistle may n

laila [671]

To solve this problem we will apply the concepts related to the Doppler effect. According to this concept, it is understood as the increase or decrease of the frequency of a sound wave when the source that produces it and the person who captures it move away from each other or approach each other. Mathematically this can be described as

$f = f_0 (\frac{v-v_0}{v})$

Here,

$f_0$ = Original frequency

$v_0$ = Velocity of the observer

$v$ = Velocity of the speed

Our values are,

$v = 340m/s \rightarrow \text{Speed of sound}$

$f = 20kHz \rightarrow \text{Apparent frequency}$

$f_0 = 21kHz \rightarrow \text{Original frequency}$

Using the previous equation,

$f = f_0 (\frac{v-v_0}{v})$

Rearrange to find the velocity of the observer

$v_0 =v (1-\frac{f}{f_0})$

Replacing we have that

$v_0= (340m/s)(1-\frac{20kHz}{21kHz})$

$v_0 = 16.19m/s$

Therefore the velocity of the observer is 16.2m/s

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3 years ago

What is the gravity force between two stars with mass of 5,000,000 kg and 1,000,000 kg if the distance between them is 100 m

Luda [366]

Answer:

0.0334N

Explanation:

Given parameters:

M1 = 5 x 10⁶kg

M2 = 1 x 10⁶kg

Distance = 100m

Unknown:

Gravitational force = ?

Solution:

To solve this problem, we use the Newton's law of universal gravitation.

Fg = $\frac{G m1 m2}{r^{2} }$

G is the universal gravitation constant

m is the mass

r is the distance

Fg = $\frac{6.67 x 10^{-11} x 5 x 10^{6} x 1 x 10^{6} }{100^{2} }$ = 0.0334N

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3 years ago

Converted to<br> Energy<br> Electricity powers the lights<br> for a building.

Slav-nsk [51]

Answer:

More than enough solar energy (8.2 million quad BTUs, 1 quad = 2.9 x1011 kWh) hits Earth's surface each year to meet all of societies' needs. Currently we use about 400 quads per year to run our society. Good building design allows passive use of sunlight to heat homes. Simple solar collectors are used to heat water and cook food. As useful as it is for these purposes, thermal energy from sunlight is still a low quality energy compared to electricity. Computers, most machinery, light bulbs, subway trains, and much more all require electricity. It is possible to turn thermal energy from the sun into electricity. In this unit we will examine how.

. We will also examine how to make electricity directly from light using the photovoltaic cells.

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3 years ago