81. [0/20 Points]DETAILSSERPSEWA10 22.WA.001.TUTORIAL.MY NOTESASK YOUR TEACHERYou hold a ruler that has a charge on its tip 2.60
1 answer:
Lets draw a diagram
In this problem, we need to balance the forces out.
First let's find what the force of gravity is on the paper so that we can figure out how much force the electrostatic force needs to be to lift the paper.
Fg = (3x10^-3)* 9.8 = .0294 N
Now we need to figure out the force required to lift the paper. We can figure the charge out with this formula (coulomb's law)
Where d is the distance, the 'q's are the charges and k is coulombs constant
Since we know the force to be .0294 N, we can set that to the Force and solve for q2
q1 = -10x10^-6 C
d = 2.6 x 10^-2 m
k = 9 x 10^9
Fe = 0.0294 N
Plugging all of these values in and solving yields us
2.21x10^-10 C = 2.21x10^-4 μC
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Answer:
a) F = 2.25 10³ N, b) REPULSIVE.
Explanation:
a) The electric force is given by coulomb's law
F = k q1q2 / r2
in this case nso indicate that the two charges have the same value
q₁ = q₂ = 2.5 10⁻⁶ C
Let's reduce the magnitudes to the SI system
r = 0.5 cm (1m / 100cm) = 5 10⁻³ m
let's calculate
F =
F = 2.25 10³ N
b) In electricity, electric charges of the same sign repel and those of the opposite sign attract
In this exercise, the balls are equal and are rubbed with the same material, for which it acquires charges of the same type, consequently, as the charges are of the same type, they indicate that the negative force is REPULSIVE.