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3 years ago

6

If you could throw an object high enough to reach space how hard would you have to throw it

1 answer:

natulia [17]3 years ago

3 0

To throw an object into the space you need to throw it with the escape velocity of the earth which is 11.2 km/sec. therefore if you can throw an object with the speed of 11.2 km/sec it will leave the earth atmosphere and will reach to the space.

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When Trinity pulls on the rope with her weight, Newton's Third Law of Motion tells us that the rope will _____.

Grace [21]

The rope will pull back against you.

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3 years ago

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A cheetah accelerates from rest to 30m/s in 3 seconds. Calculate the acceleration of the cheetah.

fiasKO [112]

30m/s times 3s= 90 m/s

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3 years ago

A Jeep Rubicon has a mass of 2,630 kg. With a momentum of 55,200 kg m/s. What was the speed, in m/s, of the vehicle?

Annette [7]

Answer:

The speed of the vehicle was 21 m/s

Explanation:

Momentum can be defined as mass in motion

Momentum depends on the variables mass and velocity

The momentum of an object is equal to the mass of the object times the

velocity of the object

The given is:

→ A Jeep Rubicon has a mass of 2,630 kg

→ With a momentum of 55,200 kg m/s

We need to find the speed of the vehicle

→ The momentum = mass × speed

Substitute the values above in the rule

→ 55,200 = 2,630 × speed

Divide both sides by 2,630

→ speed = 20.99 ≅ 21 m/s

<em>The speed of the vehicle was 21 m/s</em>

4 0

3 years ago

You have two vectors, which are 2.59 m at 30.0° north of east and 4.18 m at 60.0° north of west. What is the magnitude in meters

andrew11 [14]

Answer: $\ec{r}=0.153\hat{i}+4.914\hat{j}$ v

Explanation:

Given

Vector 1

$\vec{a}=2.59\left ( cos30\hat{i}+sin30\hat{j}\right )$

Vector 2

$\vec{b}=4.18\left ( -cos60\hat{i}+sin60\hat{j}\right )$

Resultant $\vec{r}=\vec{a}+\vec{b}$

$\vec{r}=2.59\left ( cos30\hat{i}+sin30\hat{j}\right )+4.18\left ( -cos60\hat{i}+sin60\hat{j}\right )$

$\vec{r}=0.153\hat{i}+4.914\hat{j}$

$|r|=4.916$

5 0

3 years ago

An electric kitchen range has a total wall area of 1.40 m2 and is insulated with a layer of fiberglass 4.0 cm thick. The inside

Gemiola [76]

Answer: Heat current through the insulator=196W

Electric power= 196W

Explanation: Given: Kglass = 0.040W/m

Temperature of inside glassTi=175°C

Temperature of outside glass To= 35°C

Area=1.4m^2 , L= 4×10^-2

Heat current(H)= K ×A× (Ti - To)/L

Substituting the values into the equation

H = 0.04 × K × 1.4 ×(175-35)/4×10^-2

H= 196W.

The electric power = Heat current =196W

The electric power is the magnitude of heat current

6 0

3 years ago