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zloy xaker [14]
10 months ago
12

Identify at least one Hamilton path and at least one Hamilton circuit

Mathematics
1 answer:
Anna71 [15]10 months ago
4 0

We will investigate how to determine Hamilton paths and circuits

Hamilton path: A path that connect each vertex/point once without repetition of a point/vertex. However, the starting and ending point/vertex can be different.

Hamilton circuit: A path that connect each vertex/point once without repetition of a point/vertex. However, the starting and ending point/vertex must be the same!

As the starting point we can choose any of the points. We will choose point ( F ) and trace a path as follows:

F\to D\to E\to C\to A\to B\to F

The above path covers all the vertices/points with the starting and ending point/vertex to be ( F ). Such a path is called a Hamilton circuit per definition.

We will choose a different point now. Lets choose ( E ) as our starting point and trace the path as follows:

E\to D\to F\to B\to A->C

The above path covers all the vertices/points with the starting and ending point/vertex are different with be ( E ) and ( C ), respectively. Such a path is called a Hamilton path per definition.

One more thing to note is that all Hamilton circuits can be converted into a Hamilton path like follows:

F\to D\to E\to C\to A\to B

The above path is a hamilton path that can be formed from the Hamilton circuit example.

But its not necessary for all Hamilton paths to form a Hamilton circuit! Unfortunately, this is not the case in the network given. Every point is in a closed loop i.e there is no loose end/vertex that is not connected by any other vertex.

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algol13

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Answer:

  128 miles

Step-by-step explanation:

The convict has a head start of ...

  distance = speed × time

  distance = (8 mi/h) × (14 h) = 112 mi

That distance is being closed at a rate that is the difference between the speeds, so ...

  64 mi/h -8 mi/h = 56 mi/h

The time it takes the guards to catch the convict will be ...

  time = distance/speed

  time = (112 mi)/(56 mi/h) = 2 h

The guards and prisoner will be at a distance from the prison of ...

  distance = speed × time

  distance = (64 mi/h)(2 h) = 128 mi

The convict will be caught 128 miles from the prison.

__

<em>Check</em>

The convict will run an additional (8 mi/h)(2 h) = 16 mi after the guards start pursuit. That, in addition to the 112 miles already run, will total 112+16=128 miles, the same distance the guards travel in that 2 hours.

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3 years ago
Circle 1 is centered at (−4, 5) and has a radius of 2 centimeters. Circle 2 is centered at (2, 1) and has a radius of 6 centimet
IgorC [24]
Basically, you have two circles. You are asked to take circle 1 and "move it" so that it is on top of circle 2. This process of moving is called a translation and can be thought of as sliding. You do this by ensuring that the two have the same center. So, starting at (-4,5) how do you have to move to end up at (2,1)?

To do this we need to move right 6 as the x-coordinate goes from -4 to 2. We also need to move down 4 as the y-coordinate goes from 5 to 1. So we add 6 to the x-coordinate and subtract 4 from the y-coordinate. The transformation rule is (x+6, y-4).

Once you do this the circles have the same center. Next you wish to dilate circle 1 so it ends up being the same size at circle 2. That means you stretch it out in such a way that it keeps its shape. Circle 1 has a radius of 2 centimeters and circle 2 has a radius of 6 centimeters. That is 3x bigger. So we dilate by a factor of 3.

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I hope this helps!
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