The acceleration of the proton that is projected in the positive x direction into a region of a uniform electric field is 5.76×〖10〗^13 m/s^2
The product of the field's strength and the charge's strength yields the magnitude of the electric force acting on a charge traveling in a magnetic field region.
The electric force magnitude acting on the charge is expressed in the equation below.
F=|→E|×|q|
F=|-6.00×〖10〗^5 N/C|×||+1.602×〖10〗^(-19) C|
F=9.612×〖10〗^(-14) N
Newton's second law of motion states that the magnitude of a force is equal to the product of a proton's mass and its acceleration. Where the magnitude of the acceleration of the proton is ;
a=F/m
Where F is the force and m is the mass;
Inserting the values into the equation,
a=(9.612×〖10〗^(-14) N)/(1.67×〖10〗^(-27) kg)
a=5.76×〖10〗^13 m/s^2
Therefore, the acceleration of proton is 5.76×〖10〗^13 m/s^2 #SPJ4
brainly.com/question/13263306
#SPJ4
