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Furkat [3]
4 years ago
15

True or false:slow movements of mantle rock called radiation transfer heat in the mantle.

Physics
1 answer:
RUDIKE [14]4 years ago
8 0
The best answer between the two options would be the second choice B) FALSE.
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I NEED HELP WITH NUMBER 7 I WILL GIVE U BRAINLIEST
grigory [225]

Answer:

the blue one

Explanation:

3 0
4 years ago
A motor does 20. joules of work on a block, accelerating the block vertically upward. Neglecting friction, if the gravitational
Eva8 [605]
The motor does 20 J of work on the block, it means that the total mechanical energy of the block has increased by 20 J. But the increase in total mechanical energy is equal to the sum of the increases in potential energy and kinetic energy:
\Delta E = \Delta U + \Delta K
So, if the gravitational potential energy has increased by 15 J, the kinetic energy has increased by
\Delta K = \Delta E - \Delta U = 20 J - 15 J= 5 J
4 0
3 years ago
Which terms refer to the smallest pure substances? A. mixtures and alloys B. molecules and atoms C. elements and isotopes D. met
MariettaO [177]
B. molecules and atoms
7 0
3 years ago
HURRY!!!!
VMariaS [17]

Answer:

Ted is correct

Explanation:

The equation for gravitational potential energy is PE = m·g·h

The equation for gravitational kinetic energy is KE = 1/2·m·v²

Where:

m = Mass of the object (The racing car)

g = Acceleration due to gravity

h = The height to which the object is raised

v = Velocity of motion of the object

From the principle of conservation of energy, energy can neither be created nor destroyed but changes from one form to another, we have;

Potential energy gained from location at height h = Kinetic energy gained as the object moves down the level ground

m·g·h = 1/2·m·v² canceling like terms gives

g·h = 1/2·v²

v = (√2·g·h)

If the speed is doubled, we have

2·v = 2× (√2·g·h) =  (√2·g·4·h)

Therefore, if 2·v = v₂ then v₂ =  (√2·g·4·h)

Since g, the acceleration due to gravity, is constant, it means that the initial  height must be multiplied or increased 4 times to get the new height, that is we have;

v₂ =  (√2·g·4·h) = (√2·g·h₂)

Where:

4·h = h₂

Which gives;

v₂² = 2·g·h₂

1/2·v₂² = g·h₂

1/2·m·v₂² = m·g·h₂ Just like in the first relation

Therefore, Ted is correct s they need to go up four times the initial height to double the speed.

5 0
3 years ago
The wavelengths of light emitted by a firefly span the visible spectrum but have maximum intensity near 550 nm. A typical flash
Reil [10]

Answer:

3.3\cdot 10^{15}

Explanation:

First of all, let's calculate the energy of a single photon of wavelength

\lambda=550 nm=5.5\cdot 10^{-7}m

which is given by

E_1 = \frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5.5\cdot 10^{-7} m}=3.6\cdot 10^{-19} J

The power of the flash is

P=1.2 mW=0.0012 W

and the time it lasts is

t=100 ms=0.1 s

so the total energy delivered in one flash is

E=Pt=(0.0012 W)(0.1 s)=1.2\cdot 10^{-3}J

This energy contains exactly N photons each of energy E_1, so the number of photons emitted in one flash is

N=\frac{E}{E_1}=\frac{1.2\cdot 10^{-3} W}{3.6\cdot 10^{-19}J}=3.3\cdot 10^{15}

3 0
3 years ago
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