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nikklg [1K]
2 years ago
9

{10}^{3} ) \div 3" alt="(3 \times {10}^{3} ) \div 3" align="absmiddle" class="latex-formula">I need to find 2/3 of this but it wont give me the answer to multiply :|
Mathematics
1 answer:
hoa [83]2 years ago
3 0

Given the expression :

(3\times{10}^3)\div3

We need to find 2/3 of the given

The value of the given expression will be :

\frac{3\times10^3}{3}=10^3

2/3 of the value of the result will be :

\frac{2}{3}\cdot10^3=\frac{2}{3}\cdot1000=\frac{2000}{3}=666\frac{2}{3}

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What’s the answer to this?
fgiga [73]

Answer:

87

Step-by-step explanation:

5 0
4 years ago
Given the point (3, 3.5), name a second point so that the two points form a horizontal segment.
Sati [7]

For the horizontal segment, the value of the ordinate will not change. Then the second point will be (x, 3.5).

<h3>What is coordinate geometry?</h3>

Coordinate geometry is the study of geometry using the points in space. Using this, it is possible to find the distance between the points, the dividing line is m:n ratio, finding the mid-point of the line, etc.

The point is given as (3, 3.5).

Then name a second point so that the two points form a horizontal segment.

For the horizontal segment, the value of the ordinate will not change.

Let x be the abscissa.

Then the point will be given as (x, 3.5).

More about the coordinate geometry link is given below.

brainly.com/question/1601567

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3 0
2 years ago
Five times the sum of a number and 27 is greater than or equal to six times the sum of that
AleksAgata [21]

The complete version of question:

<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>

Answer:

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

Step-by-step explanation:

As the description of the statement is:

'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>

<em />

As

  • <em>Five times the sum of a number and 27  </em>is written as: 5(x + 27)
  • <em>greater than or equal </em>is written as:  \geq
  • <em>six times the sum of that number and 26'  </em>is written as: 6(x + 26)

so lets combine the whole statement:

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

solving

<em />5\left(x\:+\:27\right)\ge \:6\left(x\:+\:26\right)<em />

<em />5x+135\ge \:6x+156<em />

<em />5x+135-135\ge \:6x+156-135<em />

<em />5x\ge \:6x+21<em />

<em />5x-6x\ge \:6x+21-6x<em />

<em />-x\ge \:21<em />

<em />\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}<em />

<em />\left(-x\right)\left(-1\right)\le \:21\left(-1\right)<em />

<em />x\le \:-21<em />

Therefore,

5\left(x+27\right)\ge \:6\left(x+26\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-21\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-21]\end{bmatrix}

6 0
3 years ago
Subtract 2m – 7q + 5 from 4p + 2q and add your result to 7m² - 3m + 9q – 1
max2010maxim [7]

212134568899999999love is love

7 0
4 years ago
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sub to my y o t u b e. my. y o u t u b e. is stiko9 the vidoe tha says oh no primo or small skate clips or slomo kickflip is my
ANEK [815]

The answer is negative 5 if Im correct

3 0
3 years ago
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