Answer:

Explanation:
The equivalent of Newton's second law for rotational motions is:

where
is the net torque applied to the object
I is the moment of inertia
is the angular acceleration
In this problem we have:
(net torque, with a negative sign since it is a friction torque, so it acts in the opposite direction as the motion)
is the moment of inertia
Solving for
, we find the angular acceleration:

The unit of measurement used in the metric system is Meters.
The metric system makes use of measurements that we often see every day. these are used to measure length, weight, and capability. you will often see these as grams, kilograms, millimetres, centimeters, meters, milliliters, and liters. The metric machine is used all around the globe as it is easy to understand.
The metric system is a system of measurement that succeeded the decimalized system primarily based on the meter that had been added in France in the 1790s.
Metrics are measures of quantitative assessment normally used for comparing and tracking performance or manufacturing. Metrics may be used in a ramification of situations. Metrics are heavily trusted in the monetary evaluation of corporations with the aid of each inner manager and external stakeholders.
Learn more about the metric system here:-brainly.com/question/1837503
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All four choices are true statements !
(I've never seen that before in a Brainly question.)
Answer:
a. keeps its speed for a short while, then slows and stops. slows steadily until it stops.
Explanation:
Since the tension in the rope, t is greater than the kinetic friction fk, the box is moving forward because there is a net force on it. That is, t - fk = f = ma.
Since there is a net force, there is an acceleration and thus an increasing velocity.
When the rope breaks, the tension, t = 0. So, t - fk = 0 - fk = -fk = ma'.
Now, the net force acting on the box is friction in the opposite direction. This force tends to slow the box down from its initial velocity at acceleration, 'a' until its velocity is zero, where it stops. Since the frictional force is constant, the acceleration, a' on the box is thus constant and the box undergoes uniform deceleration until its velocity is zero.
<u>So, the box keeps its speed for a short while, then slows and stops. slows steadily until it stops.</u>
So, the answer is a.