Which of these is an example of a physical change?

The following are examples of physical properties except

Ugo [173]

<h2>Answer:</h2><h3>D. ability to react with oxygen</h3><h2>Explanation:</h2>

Im not sure this in your choices but if it is, this is the answer.

I hope I've helped.

6 0

2 years ago

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An Austin volleyball player bumps a 5 kg ball into the air. It reaches a height of 2.8 meters. How fast was the ball going as it

KATRIN_1 [288]

Answer:

v = 7.4 m/s

Explanation:

Given that,

Mass if a volleyball, m = 5 kg

The ball reaches a height of 2.8 m

We need to find how fast the ball is going as it bumped into the air. Ket the velocity is v. Using the conservation of energy to find it as follows :

$mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 2.8} \\\\=7.4\ m/s$

So, the required speed is 7.4 m/s. Hence, the correct option is (b).

6 0

3 years ago

A car is traveling around a horizontal circular track with radius r = 220 m at a constant speed v = 16 m/s as shown. The angle θ

iogann1982 [59]

Velocity = distance / time = ( 2 * pi * r ) / t = 20.583 m/s

x component = sine ( 32 ° ) * 20.583 = 10.91 m/s

hope this helps :)

5 0

2 years ago

Suppose the student in (Figure 1) is 68kg, and the board being stood on has a 12kg mass. What is the reading on the left scale?

lesantik [10]

The equilibrium conditions allow to find the results for the balance forces are:

F₁ = 225.4 N

F₂ = 558.6 N

When the acceleration is zero we have the equilibrium conditions for both linear and rotational motion.

∑ F = 0

∑ τ = 0

Where F are the forces and τ the torques.

The torque is the product of the force and the perpendicular distance to the point of support,

The free-body diagrams are diagrams of the forces without the details of the bodies, see attached for the free-body diagram of the system.

We write the translational equilibrium condition.

F₁ - W₁ - W₂ + F₂ = 0

We write the equation for the rotational motion, set our point of origin at scale 1, and the counterclockwise turns are positive.

F₂ 2 - W₁ 1 - W₂ 1.5 = 0 $\frac{W_1 \ 1 + W_2 \ 1.5}{2}$

Let's calculate F₂

F₂ = $\frac{W_1 \ 1 + W_2 \ 1.5 }{2}$

F₂ = (m g + M g 1.5)/ 2

F₂ = $\frac{(12 + 68 \ 1.5 ) \ 9.8}{2}$

F₂ = 558.6 N

We substitute in the translational equilibrium equation.

F₁ = W₁ + W₂ - F₂

F₁ = (m + M) g - F₂

F₁ = (12 +68) 9.8 - 558.6

F₁ = 225.4 N

In conclusion using the equilibrium conditions we can find the forces of the balance are:

F₁ = 225.4 N

F2 = 558.6 N

Learn more here: brainly.com/question/12830892

5 0

2 years ago

Please help me this is timed . Find x if a = 3.0 m/s^2

storchak [24]

Answer:

x = 50 N

Explanation:

Given that we have a net force, a mass, and acceleration, we can use the fundamental formula for force found in newton's second law which is F = m × a.

Given a mass of 150 kg, and an acceleration 3.0m/s². We can substitute these two values in our formula to calculate the magnitude of these forces or it's net force to identify the unknown force acting on our known force for this situation to work.

_______

F (Net force) = F2 (Second force which we are given) - F1 (First force) = m × a

m (mass which we are given) = 150 kg

a (acceleration which we are given) = 3.0m/s

________

So F = m × a → F2 - F1 = m × a →

500 - F1 = 150 × 3.0 → 500 - F1 = 450 →

-F1 = -50 → F1 = 50

5 0

3 years ago