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Furkat [3]
1 year ago
5

Find the area of thi emi-circle with diameter, d = 8cm. Give your anwer a an expreion in term of π

Mathematics
1 answer:
GrogVix [38]1 year ago
6 0

The area of semi-circle is 8π cm² with diameter of 8cm.

What is area of semi-circle?

  • The area that the semicircle occupies is that which is contained inside its perimeter. Half of a circle is a semicircle.
  • The area of a semicircle will therefore be equal to half that of a circle. Both the radius and the diameter can be used to get the semicircle's area.
  • The formula used to determine a semicircle's area in terms of radius "r" is written as follows:

Area of circle = πr²/2

  • Area of semi-circle=  πd²/8  is the formula used to determine a semicircle's area in terms of its diameter.
  • The value of the constant is 22/7, or 3.14.

Given:

Diameter = 8cm

Area of semicircle = πd² / 8

=π8² / 8

= 8π cm²

Hence, the area of semi-circle is 8π cm².

To know more about semi-circle check the below link:

brainly.com/question/15822332

#SPJ4

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The slope point form is

y-y1=m(x-x1)

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point (-5, -4) lies on the line

x1 = -5 and y1 = -4

Let us substitute them in the form above

y-(-4)=-1(x-\lbrack-5\rbrack)

Remember (-)(-) = (+)

y+4=-1(x+5)

The equation of the line in the slope-point form is y + 4 = -1(x + 5)

6 0
1 year ago
If the smallest angle of a triangle is 20° and it is included between sides of 4 and 7, then (to the nearest tenth) the smallest
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Answer:

3.5

Step-by-step explanation:

The smallest side of a triangle is formed by the smallest angle in the triangle.

To find the side opposite (formed by) the 20 degree angle, we can use the Law of Cosines. The Law of Cosines states that for any triangle, c^2=a^2+b^2-ab\cos \gamma, where a, b, and c are the three sides of the triangle and \gamma is the angle opposite to c.

Let c be the side opposite to the 20 degree angle.

Assign variables:

  • a\implies 4
  • b\implies 7
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Substituting these variables, we get:

c^2=4^2+7^2-2(4)(7)\cos 20^{\circ},\\c^2=16+49-56\cos 20^{\circ},\\c^2=12.377213236,\\c=\sqrt{12.377213236}=3.51812638147\approx \boxed{3.5}

Therefore, the shortest side of this triangle is 3.5.

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3 years ago
Find approximate radius of a circle that has an area of 60 square centimeters
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rewona [7]
Let x and y be the sides of the rectangle. The perimeter is given to be 500m, so we are maximizing the area function A(x,y)=xy subject to the constraint 2x+2y=500.

From the constraint, we find

2x+2y=500\implies x+y=250\implies y=250-x

so we can write the area function independently of y:

A(x,y)=\hat A(x)=x(250-x)=250x-x^2

Differentiating and setting equal to zero, we find one critical point:

\dfrac{\mathrm d\hat A(x)}{\mathrm dx}=250-2x=0\implies x=125

which means y=250-125=125, so in fact the largest area is achieved with a square fence that surrounds an area of A(125,125)=125^2=15625\text{ m}^2.
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