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3 years ago

What is biomass energy

2 answers:

8 0

Industrially biomass, living or recently experienced obtain fuel from biological material or by using other industrial purposes are related. Widely, with the goal of obtaining biofuels fibers with cultivated plants, heat and chemicals used to obtain the means of animal and vegetable products. Biomass, organic waste can be burned as a fuel composition. However, geographical impact modified with, coal, organic materials such as oil-free. Are usually measured by dry weight

AysviL [449]3 years ago

3 0

Answer: Biomass energy is the use of the organic materials to generate electricity.

Explanation:

Biomass is the fuel. It is developed from the organic materials. It is renewable and sustainable source of energy. Like sugarcane, corn etc. They are used to create bio fuels.

Biomass energy is the use of the organic materials to generate electricity. The energy is produced by burning the organic material that comes from plant and animal.

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Even under the most ideal conditions, only about 8% of the internal energy of the steam produced in a steam engine can be conver

Anna71 [15]

As per the law of conservation of energy, no energy is created or destroyed. Therefore, we can conclude that the remaining 92% of energy released in electricity generation from steam power plants is converted to other, non-utilizable forms of energy. Such forms include sound energy or thermal energy between the moving parts of the plant.

8 0

4 years ago

There have been different models of the atom over time. How has the competition between these models affected our understanding

Umnica [9.8K]

Each time it gets changed we understand more about it

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3 years ago

Read 2 more answers

A car speeds up from 13 m/s to 23 m/s in 30 seconds. What is the acceleration of the car?

ra1l [238]

Well, v = u + a×t is the equation.

v: final velocity, which is 23 m/s in this equation.
u: initialo velocity = 13 m/s 
a: acceleration = ? 
t: time = 30s

Your equation would be...

23 = 13 + a×30 
a = (23 - 13) / 30 
a = 1 / 3 
a = 0.333 m/s

7 0

3 years ago

(A) What is the maximum tension possible in a 1.00-millimeter-diameter nylon tennis racket string?

attashe74 [19]

Complete Question

(A) What is the maximum tension possible in a 1.00- millimeter-diameter nylon tennis racket string?

(B) If you want tighter strings, what do you do to prevent breakage: use thinner or thicker strings? Why? What causes strings to break when they are hit by the ball?

The tensile strength of the nylon string is $600*10^{6} \ N/m^2$

Answer:

T = 471.3 \ N

To prevent breakage the thickness of the string is increased

String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension

Explanation:

From the question we are told that

The diameter is $d = 1.00 \ mm = 0.001 \ m$

The tensile strength of the nylon string is $\sigma = 600 *10^{6} \ N/m^2$

Generally the radius is mathematically evaluated as

$r= \frac{d}{2}$

=> $r = \frac{0.001}{2}$

=> $r = 0.0005 \ m$

The cross sectional area is mathematically represented as

$A = \pi r^2$

=> $A = 3.142 * (0.005)^2$

=> $A = 7.855*10^{-7}\ m^2$

Generally the tensile strength of nylon is mathematically represented as

$\sigma = \frac{T}{ A }$

Where T is the tension on the maximum tension on the string

$T = \sigma * A$

=> $T = 600*10^{6} * 7.855*10^{-7}$

=> $T = 471.3 \ N$

Form the equation above we see that

$T \ \alpha \ A$

So if the tension is increased to prevent breakage the thickness of the string is increased(i. e the cross-sectional area )

String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension

8 0

4 years ago

An automobile traveling 92.0 km/h has tires of 64.0 cm diameter. (a) What is the angular speed of the tires about their axles? (

Semenov [28]

Answer:

76.4035 m

Explanation:

r = Radius = 0.32 m

$\omega_f$ = Final angular velocity = 0

$\omega_i$ = Initial angular velocity = 92 km/h

$\alpha$ = Angular acceleration

$\theta$ = Angle of rotation

Angular speed is given by

$\omega=\dfrac{v}{r}\\\Rightarrow \omega=\dfrac{\dfrac{92}{3.6}}{0.32}\\\Rightarrow \omega=79.861\ rad/s$

The angular speed of the tires about their axles is 79.861 rad/s.

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}\\\Rightarrow \alpha=\frac{0^2-79.861^2}{2\times 2\pi \times 38}\\\Rightarrow \alpha=-13.355\ rad/s^2$

The magnitude of acceleration is 13.355 m/s²

Distance is given by

$d=\theta r\\\Rightarrow d=38\times 2\pi\times 0.32\\\Rightarrow d=76.4035\ m$

The distance moved while slowing down is 76.4035 m

6 0

3 years ago