The specific heat of hexane is 2.26 J/gºC. If 11,500 J of heat is added to

Is it safe to drive your 1600-kg car at speed 34 m/s around a level highway curve of radius 190 m if the effective coefficient o

adoni [48]

Answer:

It is unsafe

Explanation:

v = Velocity of car = 34 m/s

r = Radius of turn = 190 m

$\mu$ = Coefficient of static friction = 0.5

m = Mass of car = 1600 kg

g = Acceleration due to gravity = 9.81 m/s²

The centripetal force is given by

$F_c=m\frac{v^2}{r}\\\Rightarrow F_c=1600\frac{34^2}{190}\\\Rightarrow F_c=9734.73\ N$

The frictional force is given by

$F_f=\mu mg\\\Rightarrow F_f=0.5\times 1600\times 9.81\\\Rightarrow F_f=7848\ N$

If the centripetal force is greater than the frictional force then the car will slip which makes it unsafe.

Here, the centripetal force is greater than the frictional force which makes it unsafe to drive it at that speed.

4 0

3 years ago

A sodium ion, Na+ , has a positive charge because it

goldenfox [79]

D. lost an electron

because they have free electron in the outermost shell which they will like to denote, in order to attain stable configuration

3 0

3 years ago

Acceleration can be found by computing the slope of a blank vs .time graph

scoundrel [369]

Velocity-time graph

5 0

3 years ago

Read 2 more answers

How can we relate how gravity works to how<br> our solar system was formed?

Rzqust [24]

Answer:

gravity pulled in clouds of dust and gas. which is sometimes referred to as a nebula.

Explanation:

7 0

4 years ago

A typical running track is an oval with 74-m-diameter half circles at each end. A runner going once around the track covers a di

nirvana33 [79]

Answer:

The acceleration towards the center will be $0.43\ m/s^2$

Explanation:

Given the running track is an oval shape, and the diameter of each half-circle is 74 meters.

Also, the runner took 1 minute and 40 seconds to complete 400 m one round of the track.

We need to find the acceleration towards the center.

First, we will find the speed.

$v=\frac{d}{t}$

Where $v$ is the speed.

$d$ is the distance covered by the rider that is 400 meters.

$t$ is the time taken by the rider to complete the lap which is 1 minute and 40 seconds. $(60\ s +40\ s) = 100$ seconds.

So,

$v=\frac{400}{100}=4\ m/s$

And

$a_c=\frac{v^2}{r}$

Where $a_c$ is the acceleration towards the center.

$r$ is the radius which will be the half of the diameter 74 meters.

Hence, the radius will be 37 meters.

$a_c=\frac{4^2}{37} \\a_c=\frac{16}{37}=0.43\ m/s^2$

So, the centripetal acceleration of the rider will be $0.43\ m/s^2$

4 0

3 years ago