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Answer:
Explanation:
The magnetic force due to lower rod must be equal to weight of upper rod for equilibrium .
magnetic field due to lower rod on upper rod
= ( μ₀ / 4π ) x(2i / r ) , i is current , r is distance between rod
= 10⁻⁷ x 2 x 15 / 1.5 x 10⁻³
= 20 x 10⁻⁴ T
force on the upper rod
= B i L , B is magnetic field , i is current in second rod and L is its length
= 20 x 10⁻⁴ x 15 x .50
= 150 x 10⁻⁴ N
= .015 N
This force can balance a wire having weight equal to .015 N .
= .00153 kg
= 1.53 g .
wire should weigh 1.53 g .
The tiger's position at time <em>t</em> is given by
<em>x</em> (horizontal) = (4.5 m/s) <em>t</em>
<em>y</em> (vertical) = 7.5 m - 1/2 <em>gt</em> ²
Solve <em>y</em> = 0 for <em>t</em> to find the time it takes for the tiger to reach the ground :
0 = 7.5 m - 1/2 (9.8 m/s²) <em>t</em> ²
===> <em>t</em> = √(2 (7.5 m) / (9.8 m/s²)) ≈ 1.2 s
Evaluate <em>x</em> at this time :
<em>x</em> = (4.5 m/s) (1.2 s) ≈ 5.6 m
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hope this helps!
