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Mazyrski [523]
3 years ago
5

Two similar fans are operating in a room. Fan 1 makes a squeaking noise while running. Fan 2 is silent.

Physics
2 answers:
REY [17]3 years ago
8 0

Answer:

a

Explanation:

because it has more energy

GaryK [48]3 years ago
5 0

Answer:

d fan 2 becuase Fan 1 converts some energy into sound

Explanation:

Why is the awnser D you ask me?

Well its becuase sound is energy and to make sound you must use other energy. fan 1 uses some of its kinetic energy and converts it to sound and slows down becuase it waste kinetic energy for sound. on the other hand fan 2 converts all its electrical energy (of course it emits some infered light) into kinetic energy.

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Consider the following four objects: a hoop, a solid sphere, a flat disk, a hollow sphere. Each of the objects has mass M and ra
Svetlanka [38]

Answer:

Hoop.

Explanation:

The angular acceleration performed at a given torque:

\alpha = \frac{\tau}{I}

The moments of inertia of each element are described below:

Hoop

I = M\cdot R^{2}

Solid sphere

I = \frac{2}{5}\cdot M \cdot R^{2}

Flat disk

I = \frac{1}{2}\cdot M \cdot R^{2}

Hollow sphere

I = \frac{2}{3}\cdot M \cdot R^{2}

The greater the moment of inertia, the greater the torque to obtain the same angular acceleration. Therefore, the hoop requires the largest torque to receive the same angular acceleration.

8 0
3 years ago
What color do blind people see lol
Pachacha [2.7K]

Answer

I think most see black and white.

5 0
3 years ago
Read 2 more answers
An object has a kinetic energy of 275 j and a momentum of magnitude 25.0 kg · m/s. find the (a) speed and (b) mass of the object
Sergeu [11.5K]
Kinetic energy = momentum^2 / 2 x mass
Mass = (momentum^2/ Kinetic energy) / 2

Mass =  (25^2 / 275) / 2
Mass = 1.136 kg.

momentum = mass x velocity

velocity = mass / momentum
velocity = 1.136 / 25
velocity = 0.04544 m/s
8 0
3 years ago
Read 2 more answers
What do you mean by acceleration due to gravity? ​
likoan [24]

It is the acceleration of an object in free fall

Explanation:

When an object is in free fall, it is subjected only to one force: the force of gravity, which pulls the object downward, with a magnitude (near the Earth's surface) which is given by

F=mg

where

m is the mass of the object

g=9.8 m/s^2 is the acceleration due to gravity

We can apply Newton's second law to the object in free fall:

F=ma

where

F is the net force on the object

a is the acceleration of the object

m is the mass

However, since there is only the force of gravity acting on the object, the net force is equal to the force of gravity: so we can equate the two equations, obtaining that

mg = ma\\\rightarrow a = g

Which means that the acceleration of an object in free fall (acted upon the force of gravity only) is equal to the acceleration due to gravity, g=9.8 m/s^2.

Learn more about gravity:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

4 0
3 years ago
An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.40 kW. A receiving antenna 6
lara [203]

To solve the problem we will apply the concepts related to the Intensity as a function of the power and the area, as well as the electric field as a function of the current, the speed of light and the permeability in free space, as shown below.

The intensity of the wave at the receiver is

I = \frac{P_{avg}}{A}

I = \frac{P_{avg}}{4\pi r^2}

I = \frac{3.4*10^3}{4\pi(4*1609.34)^2} \rightarrow 1mile = 1609.3m

I = 6.529*10^{-6}W/m^2

The amplitude of electric field at the receiver is

I = \frac{E_{max}^2}{2\mu_0 c}

E_{max}= \sqrt{2I\mu_0 c}

The amplitude of induced emf by this signal between the ends of the receiving antenna is

\epsilon_{max} = E_{max} d

\epsilon_{max} = \sqrt{2I \mu_0 cd}

Here,

I = Current

\mu_0 = Permeability at free space

c = Light speed

d = Distance

Replacing,

\epsilon_{max} = \sqrt{2(6.529*10^{-6})(4\pi*10^{-7})(3*10^{8})(60.0*10^{-2})}

\epsilon_{max} = 0.05434V

Thus, the amplitude of induced emf by this signal between the ends of the receiving antenna is 0.0543V

6 0
3 years ago
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