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hjlf
1 year ago
13

Name two common fuel gases that can be used for oxyfuel cutting

Engineering
1 answer:
zlopas [31]1 year ago
8 0
Hi

Acetylene and propane

I hope this help you!
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According to the zeroth law of thermodynamics, which of the following cannot occur?
Ierofanga [76]

Answer:

Answer is B       A cooler full of ice chilling a soda sitting on top of it

Explanation:

A cooler full of ice chilling a soda sitting on top of it

3 0
3 years ago
The efficiency of a steam power plant can beincreased by bleeding off some of the steam thatwould normally enter the turbine and
3241004551 [841]

Answer:

Explanation:

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5 0
3 years ago
Underground water is to be pumped by a 78% efficient 5- kW submerged pump to a pool whose free surface is 30 m above the undergr
maksim [4K]

Answer:

a) The maximum flowrate of the pump is approximately 13,305.22 cm³/s

b) The pressure difference across the pump is approximately 293.118 kPa

Explanation:

The efficiency of the pump = 78%

The power of the pump = 5 -kW

The height of the pool above the underground water, h = 30 m

The diameter of the pipe on the intake side = 7 cm

The diameter of the pipe on the discharge side = 5 cm

a) The maximum flowrate of the pump is given as follows;

P = \dfrac{Q \cdot \rho \cdot g\cdot h}{\eta_t}

Where;

P = The power of the pump

Q = The flowrate of the pump

ρ = The density of the fluid = 997 kg/m³

h = The head of the pump = 30 m

g = The acceleration due to gravity ≈ 9.8 m/s²

\eta_t = The efficiency of the pump = 78%

\therefore Q_{max} = \dfrac{P \cdot \eta_t}{\rho \cdot g\cdot h}

Q_{max} = 5,000 × 0.78/(997 × 9.8 × 30) ≈ 0.0133 m³/s

The maximum flowrate of the pump Q_{max} ≈ 0.013305 m³/s = 13,305.22 cm³/s

b) The pressure difference across the pump, ΔP = ρ·g·h

∴ ΔP = 997 kg/m³ × 9.8 m/s² × 30 m = 293.118 kPa

The pressure difference across the pump, ΔP ≈ 293.118 kPa

6 0
2 years ago
. Bơm kiểu piston tác dụng đơn có áp suất p=0,64 Mpa và lưu lượng Q=3,5 l/s. Xác định tốc độ quay của trục bơm và công suất của
Viktor [21]

Answer:

not understand language

4 0
3 years ago
Calculate the equivalent capacitance of the three series capacitors in Figure 12-1
GrogVix [38]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Calculate the equivalent capacitance of the three series capacitors in Figure 12-1

a) 0.01 μF

b) 0.58 μF

c) 0.060 μF

d) 0.8 μF

Answer:

The equivalent capacitance of the three series capacitors in Figure 12-1 is 0.060 μF

Therefore, the correct option is (c)

Explanation:

Please refer to the attached Figure 12-1 where three capacitors are connected in series.

We are asked to find out the equivalent capacitance of this circuit.

Recall that the equivalent capacitance in series is given by

$ \frac{1}{C_{eq}} =  \frac{1}{C_{1}} + \frac{1}{C_{2}} + \frac{1}{C_{3}} $

Where C₁, C₂, and C₃ are the individual capacitance connected in series.

C₁ = 0.1 μF

C₂ = 0.22 μF

C₃ = 0.47 μF

So the equivalent capacitance is

$ \frac{1}{C_{eq}} =  \frac{1}{0.1} + \frac{1}{0.22} + \frac{1}{0.47} $

$ \frac{1}{C_{eq}} =  \frac{8620}{517}  $

$ C_{eq} =  \frac{517}{8620}  $

$ C_{eq} =  0.0599  $

Rounding off yields

$ C_{eq} =  0.060 \: \mu F $

The equivalent capacitance of the three series capacitors in Figure 12-1 is 0.060 μF

Therefore, the correct option is (c)

5 0
3 years ago
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