A 30g bullet travelling horizontally at 50 m/s penetrates 10 cm into a wooden block. The average force exerted by the block is:

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1 year ago

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1 answer:

Ket [755] · Answer 1 · 2024-04-19T03:51:29+03:00

The average force exerted by the block exists at -375 N.

<h3>How to find the average force exerted by the block?</h3>

Given:

Initial Velocity, u = 50m/s

Displacement, s = 10cm = 0.10m

Mass, m = 0.03Kg

Using the relation,

$$v^{2}-u^{2}=2 a s$

Substitute the values in the above equation, we get:

$$&0^{2}-50^{2}=2 \mathrm{a}(0.10) \\$

$$ \mathrm{a}= -12500 \mathrm{~ms}^{-2}$

We know that, f = ma

Putting the values, we get:

f = (0.03)(-12500)

f = -375 N

The average force exerted by the block exists at -375 N.

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