Find the area under the standard normal curve between z=0.19 and z=2.18. round your answer to four decimal places, if necessary.
1 answer:
The area under the standard normal curve between z=0.19 and z=2.18 is,
P(0.19<z<2.18)= 0.4101
<h3>How can we calculate the area under the curve?</h3>To calculate the The area under the standard normal curve between z=0.19 and z=2.18, we are using two things,
<u>Step 1</u>: The formula,
P(0.19<z<2.18)= P(Z<2.18)- P(Z<0.19)
<u>Step 2</u>: The statistical values of the area under the curve we get from the picture.
Now we put the known values from the picture in the above formula, we get,
P(0.19<z<2.18)= P(Z<2.18)- P(Z<0.19)
Or, P(0.19<z<2.18)= 0.9854-0.5753
Or, P(0.19<z<2.18)= 0.4101
From the above calculation we can easily conclude that,
The area under the standard normal curve between z=0.19 and z=2.18 is,
P(0.19<z<2.18)= 0.4101
Learn more about the standard normal curve:
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Answer:
The energy stored in the solenoid is 7.078 x 10⁻⁵ J
Explanation:
Given;
diameter of the solenoid, d = 2.80 cm
radius of the solenoid, r = d/2 = 1.4 cm
length of the solenoid, L = 14 cm = 0.14 m
number of turns, N = 200 turns
current in the solenoid, I = 0.8 A
The cross sectional area of the solenoid is given as;
The inductance of the solenoid is given by;
The energy stored in the solenoid is given by;
E = ¹/₂LI²
E = ¹/₂(2.212 x 10⁻⁴)(0.8)²
E = 7.078 x 10⁻⁵ J
Therefore, the energy stored in the solenoid is 7.078 x 10⁻⁵ J