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Sauron [17]
3 years ago
7

.

Physics
2 answers:
rusak2 [61]3 years ago
7 0

Answer:

Parts 1 and 2 only is the best answer.

Explanation:

Hope this helps!

Oksana_A [137]3 years ago
7 0

Answer: 1 and 2

Explanation:

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Valleys are one of the most common landforms on the Earth and they are formed through erosion or the gradual wearing down of the land by wind and water. In river valleys ​for example, the river acts as an erosional agent by grinding down the rock or soil and creating a valley

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Sound waves have the ability to cause objects to vibrate. If a paperback book is placed near a speaker and the volume of the spe
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yes with a lot of time it eventualy could be, but in short term no

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2 years ago
The sun is part of which type of galaxy?
jeka94
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3 years ago
Physical data is often used in the court system. In fact, police officers use radar to determine your speed when you are driving
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The driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.

The given parameters:

  • <em>Speed of the driver observed by the stationary police officer, Vo = 44.7 m/s</em>
  • <em>Speed of the driver, V = 26.8 m/s.</em>
  • <em>Speed limit = 60 mph</em>

The speed limit of the driver in meter per second is calculated as follows;

= 60 \ \times \frac{miles}{hour} \times \frac{1609.34 \ m}{1 \ mile} \times \frac{1 \ hr}{3600 \ s}\\\\= 26.82 \ m/s

From the speed limit, it is obvious that the driver's speed is within the limit. Thus, we can conclude that the driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.

Learn more about relative velocity here: brainly.com/question/17228388

6 0
2 years ago
A factory worker pushes a 30.0-kg crate a distance of 4.5 m along a level floor at constant velocity by pushing horizontally on
Olin [163]
The crate moves at constant velocity, this means that its acceleration is zero, so the net force acting on the crate is zero (Newton's second law). 

There are only two forces acting on the crate: the force F applied by the worker and the frictional force, acting in the opposite direction: \mu m g, where \mu=0.25 is the coefficient of friction and m=30.0 kg is the mass of the crate. Since the net force should be equal to zero, the two forces must have same magnitude, so we have:
F=\mu m g=(0.25)(30.0 kg)(9.81 m/s^2)=73.8 N
And so, this is the force that the worker must apply to the crate.
5 0
3 years ago
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