1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Law Incorporation [45]
3 years ago
12

1) Which one of the following is vector,B) MomentumC) MassA) EnergyD) Temperature​

Physics
1 answer:
yanalaym [24]3 years ago
8 0

Answer:

momentum is a vector quantity that points in the same direction as velocity

Explanation:

You might be interested in
How is your guys day going?​
faltersainse [42]
Good i’m tired how about you
4 0
3 years ago
Read 2 more answers
Two engines do same work in different time intervals.Which will have more power?​
Angelina_Jolie [31]

Answer:

who done work in less time will have more power

Explanation:

4 0
2 years ago
Based on the following equation, answer the questions below. ρ = (2γϕ + ψ)/rg where ρ [=] moles per cubic foot [mol/ft3] γ [=] j
AlekseyPX

1) Fundamental units of \Psi are [\frac{mol}{m\cdot s^2}]

2) Fundamental units of \Phi are [\frac{mol}{m^3}]

Explanation:

The equation for the variable \rho is

\rho =\frac{2\gamma \Phi+\Psi}{rg}

where we have:

\rho measured in [\frac{mol}{ft^3}]

\gamma measured in [\frac{J}{kg}]

r measured in [in]

g measured in [\frac{m}{s^2}]

We can re-write the equation as

\rho rg = 2\gamma \Phi + \Psi

And we notice that the units of the term on the left must be equal to the units of the term on the right.

This means that:

1) First of all, \Psi must have the same units of \rho r g. So,

[\rho r g]=[\frac{mol}{ft^3}][in][\frac{m}{s^2}]

However, both ft (feet) and in (inches) are not fundamental dimensions: this means that they can be expressed as meters. Therefore, the fundamental units of \Psi are

[\Psi]=[\frac{mol}{m^3}][m][\frac{m}{s^2}]=[\frac{mol}{m\cdot s^2}]

2)

The term 2\gamma \Phi must have the same units of \Psi in order to be added to it. Therefore,

[\gamma \Phi] = [\frac{mol}{m\cdot s^2}]

We also know that the units of \gamma are [\frac{J}{kg}], therefore

[\frac{J}{kg}][\Phi]= [\frac{mol}{m\cdot s^2}]

And so, the fundamental units of \Phi are

[\Phi]= [\frac{mol\cdot kg}{J\cdot m\cdot s^2}]

However, the Joules can be written as

[J]=[kg][\frac{m^2}{s^2}]

Therefore

[\Phi]= [\frac{mol\cdot kg}{(kg \frac{m^2}{s^2})\cdot m\cdot s^2}]=[\Phi]= [\frac{mol}{m^3}]

#LearnwithBrainly

7 0
3 years ago
4. Two people each have a mass of 55 kg. They are both in an
mestny [16]

Answer:

350 N

Explanation:

F=ma

f = force \\ m = mass \\ a = acceleration

m = 2(55kg) + 240kg \\ a = 1.0 \frac{m}{ {s}^{2} }

Force = 350 Newtons

4 0
2 years ago
something that is figurative place where a person locates the source of responsibility in his or her life.
ahrayia [7]
What is your choses .becuse it mit be a place 


4 0
3 years ago
Other questions:
  • What would happen if you held the South Pole of one magnet near the North Pole of another magnet of the same size?
    5·2 answers
  • If a photon has a frequency of 1.15 × 1015 hertz, what is the energy of the photon? Given: Planck's constant is 6.63 × 10-34 jou
    7·2 answers
  • What is the speed of light in a vacuum
    7·2 answers
  • What is the name given to a material with zero resistance that can conduct electricity without a loss of energy?
    7·1 answer
  • Elabora una tabla, como la del ejemplo, con los resultados obtenidos en los test que desarrollaste en actividades anteriores. Lu
    9·1 answer
  • Question 25
    10·1 answer
  • PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer this correctly!!!! (50pts)
    10·1 answer
  • Question 1 of 10
    11·2 answers
  • If a girl running along a straight road with a uniform velocity 1.5m/s,find her acceleration
    12·1 answer
  • How much does the Earth weigh?<br><br><br><br> Have an AWESOME day<br> -NaomiTheGenuis
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!