Answer:
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Answer:
v = 98.75 km/h
Explanation:
Given,
The distance driver travels towards the east, d₁ = 135 km
The time period of the travel, t₁ = 1.5 h
The halting time, tₓ = 46 minutes
The distance driver travels towards the east, d₂ = 215 km
The time period of the travel, t₁ = 2 h
The average speed of the vehicle before stopping
v₁ = d₁/t₁
= 135/1.5
= 90 km/h
The average speed of vehicle after stopping
v₂ = d₂/t₂
= 215/2
= 107.5 km/h
The total average velocity of the driver
v = (v₁ +v₂) /2
= (90 + 107.5)/2
= 98.75 km/h
Hence, the average velocity of the driver, v = 98.75 km/h
Answer:
mas of water displaced = 41.4 g
Explanation:
Weight in air = True weight = 45 g
Apparent weight = 3.6 g
Apparent weight = True weight - Buoyant force
Buoyant force = 45 g - 3.6 g = 41.4 g
Weight of water displaced = Buoyant force
Weight of water displaced = 41.4 g dyne
mas of water displaced = 41.4 g
Answer:
Explanation:
If air resistance is ignored and assume UP and Toward Jason are the positive directions.
horizontal analysis
d = (vx₀)t
t = d/vx₀
horizontal analysis
0 = vy₀t + ½gt²
0 = vy₀(d/vx₀)+ ½g(d/vx₀)²
as vy₀ = v₀sin45 and vx₀ = v₀cos45 and are equal.
0 = d + ½g(d²/v₀²cos²45)
-d = ½g(d²/v₀²cos²45)
-dv₀² = ½g(d²/cos²45)
v₀² = -½g(d/cos²45)
v₀² = -½(-9.81(32.0/cos²45)
v₀² = 313.92
v₀ = 17.717787...
v₀ = 17.7 m/s