4 years ago

Hich of the following equations is balanced correctly?

1 answer:

3 0

A. the carbons are unbalanced B. the hydrogens are unbalanced. D. the chlorines are unbalanced. That leaves C. to be correctly balanced.

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A sample of gold has a volume of 2 cm3 and a mass of 38.6 grams. What would be the density, and three other properties of the sa

lukranit [14]

The density of the gold is calculated to be "19,300 kg/m³".

<u>Explanation:</u>

Given:

Volume = 2cm³

Mass = 38.6 grams.

To Find:

Density of the gold = ?

Solution:

Density is obtained by dividing mass of the sample by its volume and it is given in the units of kg/m³.

Mass in grams is converted into kg as,

1 g = 0.001 kg

38. 6 g = $\frac{38.6}{1000} = 0.0386 kg$

Now we have to convert cm³ to m³ as,

1 cm³ = 10⁻⁶ m³

2 cm³ = 2 × 10⁻⁶ m³

So Density = $\frac{0.0386 k g}{2 \times 10^{-6} m^{3}}=19,300 \mathrm{kg} / \mathrm{m}^{3}$

Physical properties of Gold:

Gold is a heavy metal.

It is Malleable and ductile.

It is a corrosion resistant element.

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3 years ago

Un objeto tiene una masa de 120 kg y un volumen de 5 m3

melisa1 [442]

Answer: dont ever worry mate

Explanation:

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3 years ago

Suppose that a sled is accelerating at a rate of 2 m/s^2. if the net force is tripled and the mass is doubled, then what is the

Gwar [14]

So new acceleration is 3 m/s^2

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3 years ago

Select the correct answer. A ball is thrown straight down from the top of a building at a velocity of 16 ft/s. The building is 4

BartSMP [9]

Answer:

The ball takes 5s to reach the ground

Explanation:

in order to solve this problem we use the kinematics equation with gravity as acceleration:

$h=v_0t+1/2*gt^2$

we replace the values

$0=1/2*32t^2+16t-480$

We solve this quadratic equation:

t=5s

t=-6s (this solution has not physical sense)

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3 years ago

A thin rod of length 1.4 m and mass 180 g is suspended freely from one end. It is pulled to one side and then allowed to swing l

prisoha [69]

Answer:

$K.E = 0.1905 J$

Explanation:

From the question we are told that:

Length $L=1.4m$

Mass $m=180g$

Angular Velocity $\omega=1.80rads/s$

Generally the equation for Kinetic energy K.E is mathematically given by

$K.E =0.5 (1/3 ML^2 )w^2$

$K.E =0.5 ( 1/3 * 0.18 * 1.4^2 ) 1.8^2$

$K.E = 0.1905 J$

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3 years ago