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Thepotemich [5.8K]
1 year ago
11

-i+ (9-5i)-3(2-6i) in standard form with explanation

Engineering
1 answer:
Jobisdone [24]1 year ago
6 0

The given expression can be represented as 3+12i.

<h3>Complex Number</h3>

A complex number is represented by the following form: a+bi, where a and b are real numbers.  The variables: a is the real part and bi imaginary part. See an example: 5 + 2i , then:

  • 5 real part
  • 2i imaginary part

Regarding operations math, the same properties used for real numbers can be applied to complex numbers. And for solving the operations math with these numbers, it is important to know that i²= -1. Thus, 3i² = 3*(-1)= -3.

When you subtract or sum complex numbers, you can only subtract or sum: the real part with the real part of each complex number and the imaginary part with the imaginary part of each complex number. Here, you can see examples:

(5 + 2i) + (5 + 2i) = 10+4i

(4 + 10i) - (2 + 5i) = 2+5i

Therefore, the result for the -i+ (9-5i)-3(2-6i)  will be:

-i + 9 -5i -6+18i

-6i +3 +18i

3+12i

Read more about the complex number here:

brainly.com/question/5564133

#SPJ1

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