In a solution that is 90% ethyl alcohol and 10% water, the solute is 10 g and the solvent is 90 g.
given that :
The solute in the solution by mass percent = 10 %
mass percent = ( mass of solute / mass of solution ) × 100%
mass of solute in the solution is = 10 g
The solvent present in solution by mass percent = 90 %
the mass of solvent in the solution is is 90 g
Thus, In a solution that is 90% ethyl alcohol and 10% water, the solute is 10 g and the solvent is 90 g.
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