All categories

1 year ago

A solid is heated to a liquid and then to a gas. How many changes of state typically occur in the process?.

1 answer:

6 0

Usually, the state occurs during the process. As opposed to melting into a liquid, sublimation is the process through which a solid transforms into a gaseous state.

<h3>What solidifies?</h3>

Because the mobility of atoms lowers when individuals occupy a reasonably organized, tri structure, a solid emerges from a liquid or gas. Solids different between gasses and liquids in that they possess certain properties.

<h3>Does strong imply good?</h3>

Solid may appear to be a straightforward term at first glance, but it actually has a variety of meanings. A reliable buddy is dependable. It was pretty excellent, but not amazing, if you deliver a great showing. Similarly, if you succeed in winning convincingly, you accomplish this by a sizable but not overpowering margin.

To know more about Solid visit:

brainly.com/question/17061172

#SPJ4

You might be interested in

In flight, a rocket is subjected to four forces; weight, thrust, lift, and drag. Forces are vector quantities that have both a m

Flura [38]

Answer:

thrust

Explanation:

4 0

3 years ago

Read 2 more answers

A 1 m3tank containing air at 10oC and 350 kPa is connected through a valve to another tank containing 3 kg of air at 35oC and 15

Sveta_85 [38]

Answer:

- the volume of the second tank is 1.77 m³

- the final equilibrium pressure of air is 221.88 kPa ≈ 222 kPa

Explanation:

Given that;

$V_{A}$ = 1 m³

$T_{A}$ = 10°C = 283 K

$P_{A}$ = 350 kPa

$m_{B}$ = 3 kg

$T_{B}$ = 35°C = 308 K

$P_{B}$ = 150 kPa

Now, lets apply the ideal gas equation;

$P_{B}$ $V_{B}$ = $m_{B}$ R $T_{B}$

$V_{B}$ = $m_{B}$ R $T_{B}$ / $P_{B}$

The gas constant of air R = 0.287 kPa⋅m³/kg⋅K

we substitute

$V_{B}$ = ( 3 × 0.287 × 308) / 150

$V_{B}$ = 265.188 / 150

$V_{B}$ = 1.77 m³

Therefore, the volume of the second tank is 1.77 m³

Also, $m_{A}$ = $P_{A}$ $V_{A}$ / R $T_{A}$ = (350 × 1)/(0.287 × 283) = 350 / 81.221

$m_{A}$ = 4.309 kg

Total mass, $m_{f}$ = $m_{A}$ + $m_{B}$ = 4.309 + 3 = 7.309 kg

Total volume $V_{f}$ = $V_{A}$ + $V_{B}$ = 1 + 1.77 = 2.77 m³

Now, from ideal gas equation;

$P_{f}$ = $m_{f}$ R $T_{f}$ / $V_{f}$

given that; final temperature $T_{f}$ = 20°C = 293 K

we substitute

$P_{f}$ = ( 7.309 × 0.287 × 293) / 2.77

$P_{f}$ = 614.6211119 / 2.77

$P_{f}$ = 221.88 kPa ≈ 222 kPa

Therefore, the final equilibrium pressure of air is 221.88 kPa ≈ 222 kPa

6 0

3 years ago

The thunderbolt bobsled team is training for Olympic Gold. During practice they start a run with a speed of 0.57 m/s, they compl

aleksandr82 [10.1K]

$acceleration=\frac{\Delta\ velocity}{\Delta\ time}\\\\
v_{initial}=0,57m/s\\
distance=1360m\\ \Delta\ time=89,49seconds\\\\
v_{final}-v_{initial}=\frac{distance}{time}\\
v_{final}=\frac{distance}{time}+v_{initial}\\
v_{final}=\frac{1360}{89,49}+0,57\\\\v_{final}=15,77\frac{m}{s}\\\\
acceleration=\frac{15,77-0,57}{89,49}=0,17\frac{m}{s^2}\\\\ \boxed{acceleration=0,17\frac{m}{s^2}}$

6 0

4 years ago

The specific heat of a solid Y is 11.5 cal/g°C. A sample of this

fgiga [73]

The sample of the solid in grams is 5.5g

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

The quantity of heat absorbed or released by a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

Q = quantity of heat absorbed/released (cal)

m = mass of the substance (g)

c = specific heat (cal/g°C)

∆T = change in temperature (°C)

According to the information provided in this question:

Q = 7.90Kcal = 7900cal

m = ?

c = 11.5 cal/g°C

T1 = 135K = 135K − 273.15 = -138.1°C

T2 = 260K = 260K − 273.15 = -13.15°C

∆T = -13.15 - (-138.1) = 124.95°C

Hence, the mass of the substance can be calculated as follows:

m = Q ÷ c∆T

m = 7900 ÷ (11.5 × 124.95)

m = 7900 ÷ 1436.93

m = 5.5grams.

Therefore, the sample of the solid in grams is 5.5g.

Learn more: brainly.com/question/21643161?referrer=searchResults

5 0

2 years ago

what would someones mass be if their weight was 158.4? This is for science homework, they gave me a random weight # but no mass.

bekas [8.4K]

ON EARTH, every kilogram of mass weighs about 2.205 pounds.

So if you know the weight (in pounds), and you know that it was
weighed on Earth, you can simply divide the pounds by 2.205 ,
and you'll get the mass (in kilograms).

I can see that on this science homework, they used 2.2 for the weight
of 1 kilogram expressed in pounds. So just divide the weight by 2.2
to get the mass in kilograms.

(The weight number they gave you is not so random. :-) )

8 0

3 years ago