Answer: a. ) What is the magnitude of their average acceleration (in m/s2)
Answer:
106.03 meters
Explanation:
The height is given by the formula for motion under the influence of gravity.
h = -4.9t^2 +162.7
Height is 0 when ...
0 = -4.9t^2 +162.7
4.9t^2 = 162.7
t^2 = 162.7/4.9
t = √(162.7/4.9)
The horizontal distance traveled in that time is ...
(18.4 m/s)√(162.7/4.9) s ≈ 106.03 m
The object will strike the ground about 106.03 meters from the base of the cliff.
Explanation:
Let x = distance of 
from the fulcrum and let's assume that the counterclockwise direction is positive. In order to attain equilibrium, the net torque 
about the fulcrum is zero:
Solving for <em>x</em>,
