The total electric potential at the center of the square due to the four charges is V = √2Q/πÈa.
<h3>What do you mean by electric potential? </h3>
The amount of work needed to move a unit charge from a reference point to a specific point against an electric field. It's SI unit is volt.
V = kq/r
Where V represents electric potential, K is coulomb constant, q is Charge and r is distance between any two around charge to the point charge.
Electric potential at O due to four charges is given by,
V = 4KQ/ r
where, r = √2a/2 = a/√2
V = 4k × Q√2/a
V = √2Q/πÈa
The total electric potential at the center of the square due to the four charges is V = √2Q/πÈa.
To learn more about electric potential refer to:
brainly.com/question/12645463
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<span>
The weight of the water displaced is the same as the total weight of the
wood block. The fact that 1/3 of the block is above the water level
does not matter if you just weigh the total block of wood , then the
weight of the total block of wood = the weight of the water displaced by
the block of wood. If you want to find density of the block of wood
that is a different question - then you need the volume of the block of
wood and the information about one- third of the total weight . I hope this helped</span>
Density is mass per unit volume.
Answer:
(a) 9.0 V (b) 1.5 V (c) 6.0 V
Explanation:
Here we use the simple concept of Kirchhoff's voltage law that potential in series will be added and potential in parallel will be same always. By this concept we answer all 3 parts of this question.
(a) When six 1.5 V batteries are is series means their potential is added.
So, Voltage across six batteries is
So, Net voltage is 9.0 Volts.
(b)When six 1.5 V batteries are in parallel then the net voltage across them will be voltage of either battery.
So, Voltage is
Net voltage is 1.5 Volts.
(c) Now 3 are in series and 3 are in parallel,
the Net voltage of parallel is 1.5 V , now it behaves like <u>four </u>1.5 V are in series so the net voltage become
Net voltage is 6.0 Volts.
