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vampirchik [111]
3 years ago
11

g calculate the quantity of energy produced per gram of uranium 235 for the neutron induced Fusion of uranium

Chemistry
1 answer:
Debora [2.8K]3 years ago
7 0

Answer:

Energy released by 1 g of U-235 = 7.603 * 10¹⁰ J

Explanation:

Uranium-235, U-235 undergoes neutron-induced fission to give the following products:

1 neutron + ²³⁵U --> ¹⁴¹Ba + ⁹²Kr + 3 neutrons

Masses of reactants and products:

neutron = 1.009 amu, uranium-235 = 235.044 amu, Ba-141 = 140.910 amu, Kr-92 = 91.910 amu

mass defect = mass of reactants - mass of products

mass defect = (235.044 + 1.009) - (140.910 + 91.910 + 3 * 1.009)

mass defect = 236.053 - 235.847 = 0.206 amu

1 amu = 1.6 * 10⁻²⁷ kg

Using E = mc²

E = 0.206 * 1.6* 10⁻²⁷ kg * (3 * 10⁸ m/s)² = 2.966 * 10⁻¹¹ J

therefore, 1 atom of U-235 releases 2.966 * 10⁻¹¹ J of energy

energy released by 1 g of U-235 can be calculated as follows:

1 mole or 253 g  of U-235 contains 6.02 * 10³ atoms

1 g of U-235 will contain 6.02 * 10³/235 = 2.563 * 10²¹ atoms

Energy released by 1 g of U-235 = 2.563 * 10²¹ * 2.966 * 10⁻¹¹ J = 7.603 * 10¹⁰ J

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Which of the following statements about material bonding is correct? C O a. Ionic bonds are formed by the sharing of valence ele
Zina [86]

Answer: Option (b) is the correct answer.

Explanation:

In material bonding, there occurs Vander waal foces between the molecules in which their is either an induced or permanent dipole moment that attract molecules towards each other.

And, due to these forces the molecules are held together.

On the other hand, in a ionic bond there will always be transfer of electrons from one atom to another. This is because on atom which loses its valence electrons acquires a positive charge and another atom which gains the electrons acquires a negative charge.

Hence, these opposite charges strongly gets attracted towards each other forming a strong bond.

Whereas in a covalent bond, there will be sharing of electrons between the combining atoms.

In a metallic bond, there occurs a sea of electrons which is uniformly distributed throughout the solid substance or material.

Thus, we can conclude that the statement, Van der Waals bonds are formed by Van der Waals forces in which molecules or atoms have either an induced or permanent dipole moment to attract each other, about material bonding is correct.

5 0
3 years ago
Please help me for question 1 and 2
likoan [24]

Answer:-

1) 6 mol

2) Mo

Explanation: -

Mass of Ozone = 48 g

Chemical formula of ozone = O3

Molar mass of Ozone O 3 = 16 x 3 = 48 g mol-1

Number of moles of ozone = Mass / molar mass

= 48 g / 48 g mol-1

= 1 mol

According to Avogadro’s law, 1 mole of a substance has 6.02 x 10^ 22 molecules.

So 1 mol of O3 has 6.02 x 10^ 22 molecules of ozone.

Now each Ozone molecule has 3 atoms of oxygen.

So, 1 mol of ozone has 3 x 6.02 x 10^22 atoms of oxygen.

Sodium must have 2 x 3 x 6.02 x 10^22 atoms as per the question.

According to Avogadro’s law, 6.02 x 10^ 22 atoms are in 1 mol of sodium

So, for 2 x 3 x 6.02 x 10^22 atoms, there should be (1/ 6.02 x 10^ 22) x 2 x 3 x 6.02 x 10^22

= 6 mol of sodium.

b)

Let the mass of M be m g

Formula of hexafluoride = MF6.

Mass of the hexafluoride = g + 6 x 19

= m + 114

Mass of M=0.250g

Moles of M = 0.250/m

Mass of MF6= 0.547g

Moles of MF6 = 0.547/ (m + 114)

We know 1 mole of M gives 1 mole of MF6.

0.250/m moles of M gives 0.250/m moles of MF6.

But number of moles of MF6 = 0.547/ (m + 114)

Thus

0.250/m = (0.547)/ (m +114))

0.250m + 0.250 x 114 = 0.547m

m = 0.250 x 114 / (0.547 -0.250)

= 96

We see from the given data that Mo is 96.

So M is Mo.

4 0
3 years ago
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iii. At 50 degrees C, a saturated ammonium chloride solution will have 50.6 grams of salt per 100 g water. At 20 degrees C, the solution can hold only 37.3 grams of salt per 100 g water. Thus, 13.3 grams of salt will precipitate per 100 grams of water.
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