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3 years ago

What is the conversion for 5 g + 3.3 mL =

Chemistry

1 answer:

Dominik [7]3 years ago

3 0

Answer:

9 g/ml

Explanation:

5 + 3.3 = 8.5

But you should use sig figs.

5 has no tenths, hundredths, and etc.

Therefore the 8.5 rounds up to 9

So the answer is 9.

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If I add a proton to an atom, which of the following will change? (select all that apply) a)the type of element b)The mass of th

nirvana33 [79]

The type of element will change and the mass of the atom will change; A and B

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3 years ago

If the bucket were left outside on a hot day but brought inside before any evaporation occurred, how would the mass be affected?

dangina [55]

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3 years ago

Read 2 more answers

What is the hydroxide [OH-] concentration of a solution that has a pOH of 4.90? 14 14 1.26 x10-5 1.26 x10, -5 9.1 9.1 7.94 x 104

polet [3.4K]

Answer:

The hydroxide [OH-] concentration of the solution is 1.26*10⁻⁵ M.

Explanation:

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution.

POH indicates the concentration of hydroxyl ions [OH-] present in a solution and is defined as the negative logarithm of the activity of hydroxide ions (that is, the concentration of OH- ions):

pOH= -log [OH-]

A solution has a pOH of 4.90. Replacing in the definition of pOH:

4.90= -log [OH-]

Solving:

-4.90= log [OH-]

1.26*10⁻⁵ M= [OH-]

<u><em>The hydroxide [OH-] concentration of the solution is 1.26*10⁻⁵ M.</em></u>

3 0

3 years ago

If you have a 200.0 gram sample of carbon, how many moles of carbon do you have? A. 200.0 B. 17.0 C. 16.66 D. 12.01

lukranit [14]

Answer:

B. 17.0.

Explanation:

Hello!

In this case, considering that based on the atomic mass of the carbon atom, which means that 1 mole of carbon weights 12.01 grams, we can set up the following proportional factor to compute the moles of carbon in 200.0 grams:

$200.0gC*\frac{1molC}{12.01gC}\\\\17.0molC$

Thus, the answer would be B. 17.0.

Best regards!

7 0

3 years ago

1.5mol C3H8 from C3H8+5O2-->3CO2+4H2O .how many grams of carbon dioxide are produced

koban [17]

Answer:

$\large \boxed{\text{200 g CO}_{{2}}}$

Explanation:

We will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

Mᵣ: 44.01

C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O

n/mol: 1.5

1. Calculate the moles of CO₂

The molar ratio is 3 mol CO₂:1 mol C₃H₈

$\rm \text{Moles of CO}_{2} = \text{1.5 mol C$_{3}$H}_{8} \times \dfrac{\text{3 mol CO}_{2}}{\text{1 mol C$_{3}$H}_{8}} =\text{4.5 mol CO}_{2}$

2. Calculate the mass of CO₂.

$\text{Mass of CO}_{2} = \text{4.5 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO$_{2}$}} = \textbf{200 g CO}_{\mathbf{2}}\\\text{The reaction will form $\large \boxed{\textbf{200 g CO}_{\mathbf{2}}}$}$

3 0

3 years ago