Answer:
CH₃COOH + NaOH → NaCH₃COO + H₂O
CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻ pKa = 4.75
Explanation:
Acetic acid and NaOH make a neutralization reaction, where a salt and water are formed.
CH₃COOH + NaOH → NaCH₃COO + H₂O
Acetic acid gives protons to medium
NaOH gives hydroxides to medium
When we have protons and hydroxides, we can produce water. That's why it is a neutralization reaction.
The acid is weak, so the formed CH₃COO⁻ becomes in the conjugate strong base. This anion can make hydrolysis to water.
CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻ pKa = 4.75
The NaOH is a strong base, so the Na⁺, as the conjugate weak acid, can't make hydrolysis.
We can't make this equilibrium.
Na⁺ + H₂O ⇄ NaOH + H⁺ IMPOSSIBLE
Answer:
The cell membrane is, The thin membrane that forms the outer surface of the protoplasm of a cell
Answer:
type the question brainly, someone already answered
Explanation:
Answer:
The answer to your question is: C2 = 0.0004 M
Explanation:
Data
pH = 2.5; V = 1.0 L
V2 = 8.0 L C2 = ?
Formula
C1V1 = C2V2
C2 = C1V1 / V2
pH = -log[H⁺]
Process
[H⁺] = antilog -pH
[H⁺] = antilog (-2.5)
[H⁺] = 0.003 M = C1
Finally
(0.003)(1 l) = C2(8)
C2 = 0.003 / 8
C2 = 0.0004 M
Nitrate
Hope this helps :))
