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worty [1.4K]
3 years ago
13

I need help with this anyone?

Chemistry
1 answer:
valkas [14]3 years ago
5 0
Just look it up on goog^le or a chart
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If a sample of 4 moles of gas has a pressure of 567.42 kPa and a volume of 12.0 L, what is it's temperature?
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Your answer is b, hope this helps ;)
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3 years ago
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This experiment is more about understanding the colligative properties of a solution rather than the determination of the molar
Afina-wow [57]
Colligative properties are properties of solutions that result from adding solute to a solvent and that depend on the concentration of solute particles, but independent of the identity of the solute molecules or ions. The four colligative properties are boiling point elevation, freezing point depression, osmotic pressure, and vapor pressure lowering. 
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Answer:

Explanation:

Any substance that contains only one kind of an atom is known as an element. Because atoms cannot be created or destroyed in a chemical reaction, elements such as phosphorus (P4) or sulfur (S8) cannot be broken down into simpler substances by these reactions.

Example: Water decomposes into a mixture of hydrogen and oxygen when an electric current is passed through the liquid. Hydrogen and oxygen, on the other hand, cannot be decomposed into simpler substances. They are therefore the elementary, or simplest, chemical substances - elements.

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The elements can be divided into three categories that have characteristic properties: metals, nonmetals, and semimetals. Most elements are metals, which are found on the left and toward the bottom of the periodic table. A handful of nonmetals are clustered in the upper right corner of the periodic table. The semimetals can be found along the dividing line between the metals and the nonmetals.

4 0
3 years ago
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Given the density of iron (Fe) is 7.87 g/cm3, determine the mass of iron (in grams) in a rectangle block with the dimensions of
guapka [62]

Answer:

m=14,105.71 g Fe

Explanation:

Hello,

In this case, the first step is to compute the volume of the block considering the length, height and width:

V=L \times W \times H =12.5 in\times 3.50 in \times 2.50 in =109.375 in^3

Then, we compute the volume in cubic centimetres:

V=109.375in^3\times \frac{16.3871 cm^3}{1in^3} =1792.34cm^3

Finally, as the density is given by:

\rho =\frac{m}{V}

We solve for the mass:

m=\rho \times V= 7.87\frac{g}{cm^3} \times 1792.34 cm^3\\\\m=14,105.71 g Fe

Best regards.

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3 years ago
The percent yield of a reaction in 2 points which 52 grams of a reactant is expected to yield 30 grams of product is 25%. What i
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Answer:

idk

Explanation:

dong know

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