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Alika [10]
3 years ago
14

It's science pls help ​

Chemistry
1 answer:
GREYUIT [131]3 years ago
3 0

Answer:

1.5

Explanation:

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Jamie works at a company that makes cleaning chemicals. She is trying to make a chemical that smells like flowers. She took two
son4ous [18]

Answer:

c

Explanation:

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3 years ago
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If the human body contains about 50 deciliters of blood, and the blood has about 15 grams of hemoglobin per deciliter, and all o
Tcecarenko [31]

Answer:

The blood will contain 750 grams of O2

Explanation:

Volume of blood in the human body = 15 deciliters

Mass of hemoglobin per deciliter of blood = 15 grams

Mass of hemoglobin in 50 deciliters of blood = 50×15 = 750 grams

Since all the hemoglobin molecules are saturated with O2, mass of O2 in the blood will be the same as mass of hemoglobin molecules in the blood.

Therefore, mass of O2 in the blood is 750 grams

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3 years ago
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Calculate the molarity of a solution consisting of 65.5 g of K2S0 4 in 5.00 L of solution. ​
tia_tia [17]

Answer:

<u>Molarity</u><u> </u><u>is</u><u> </u><u>0</u><u>.</u><u>0</u><u>7</u><u>5</u><u> </u><u>M</u><u>.</u><u> </u>

Explanation:

Moles:

{ \tt{ =  \frac{65.5}{RFM} }}

RFM of potassium sulphate :

{ \tt{ = (39 \times 2) + 32 + (16 \times 4)}} \\  = 174 \: g

substitute:

{ \tt{moles =  \frac{65.5}{174}  = 0.376 \: moles}}

In volume of 5.00 l:

{ \tt{5.00 \: l  = 0.376 \: moles}} \\ { \tt{1 \: l = ( \frac{0.376}{5.00} ) \: moles}} \\ { \tt{molarity = 0.075 \: mol \: l {}^{ - 1} }}

8 0
3 years ago
N204(0) + 2NO2(g)
user100 [1]

setup 1 : to the right

setup 2 : equilibrium

setup 3 : to the left

<h3>Further explanation</h3>

The reaction quotient (Q) : determine a reaction has reached equilibrium

For reaction :

aA+bB⇔cC+dD

\tt Q=\dfrac{C]^c[D]^d}{[A]^a[B]^b}

Comparing Q with K( the equilibrium constant) :

K is the product of ions in an equilibrium saturated state  

Q is the product of the ion ions from the reacting substance  

Q <K = solution has not occurred precipitation, the ratio of the products to reactants is less than the ratio at equilibrium. The reaction moved to the right (products)

Q = Ksp = saturated solution, exactly the precipitate will occur, the system at equilibrium

Q> K = sediment solution, the ratio of the products to reactants is greater than the ratio at equilibrium. The reaction moved to the left (reactants)

Keq = 6.16 x 10⁻³

Q for reaction N₂O₄(0) ⇒ 2NO₂(g)

\tt Q=\dfrac{[NO_2]^2}{[N_2O_4]}

Setup 1 :

\tt Q=\dfrac{0.0064^2}{0.098}=0.000418=4.18\times 10^{-4}

Q<K⇒The reaction moved to the right (products)

Setup 2 :

\tt Q=\dfrac{0.0304^2}{0.15}=0.00616=6.16\times 10^{-3}

Q=K⇒the system at equilibrium

Setup 3 :

\tt Q=\dfrac{0.230^2}{0.420}=0.126

Q>K⇒The reaction moved to the left (reactants)

8 0
3 years ago
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Li²O, # of Elements and Atoms ​
sineoko [7]

Answer:Lithium atomic orbital and chemical bonding information. There are also tutorials on the first thirty-six elements of the periodic table includes: Li²O

7 0
3 years ago
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