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Alika [10]
3 years ago
14

It's science pls help ​

Chemistry
1 answer:
GREYUIT [131]3 years ago
3 0

Answer:

1.5

Explanation:

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A cylinder was charged with 1.25 atm of oxygen gas, 6.73 atm of argon, and 0.895 atm of xenon. What is the mole fraction of each
katrin2010 [14]

Considering the Dalton's partial pressure, the mole fraction of each gas is:

  • x_{oxygen}= 0.14
  • x_{argon}= 0.76
  • x_{xenon}= 0.10

<h3>Dalton's partial pressure</h3>

The pressure exerted by a particular gas in a mixture is known as its partial pressure.

So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

P_{T} =P_{1} +P_{2} +...+P_{n}

where n is the amount of gases in the gas mixture.

This relationship is due to the assumption that there are no attractive forces between the gases.

Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture. The mole fraction is a dimensionless quantity that expresses the ratio of the number of moles of a component to the number of moles of all the components present.

So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:

P_{A} =x_{A} P_{T}

In summary, the total pressure in a mixture of gases is equal to the sum of partial pressures of each gas.

Mole fraction of each gas

In this case, you know that:

  • P_{oxygen }= 1.25 atm
  • P_{argon}= 6.73 atm
  • P_{xenon}= 0.895 atm
  • P_{T} =P_{oxygen} +P_{argon}+P_{xenon}= 1.25 atm + 6.73 atm + 0.895 atm= 8.875 atm

Then:

  • P_{oxygen} =x_{oxygen} P_{T}
  • P_{argon} =x_{argon} P_{T}
  • P_{xenon} =x_{xenon} P_{T}

Substituting the corresponding values:

  • 1.25 atm= x_{oxygen} 8.875 atm
  • 6.73 atm= x_{argon} 8.875 atm
  • 0.895 atm= x_{xenon} 8.875 atm

Solving:

  • x_{oxygen}= 1.25 atm÷ 8.875 atm= 0.14
  • x_{argon}= 6.73 atm÷ 8.875 atm= 0.76
  • x_{xenon}= 0.895 atm÷ 8.875 atm=0.10

In summary, the mole fraction of each gas is:

  • x_{oxygen}= 0.14
  • x_{argon}= 0.76
  • x_{xenon}= 0.10

Learn more about Dalton's partial pressure:

brainly.com/question/14239096

brainly.com/question/25181467

brainly.com/question/14119417

#SPJ1

3 0
2 years ago
PLZ HELP QUICK!!
MissTica
I have the same question too!!!Dang I thought I would get a answer I just guessed
8 0
3 years ago
I only have 3 questions left for this, please help!!!!
kakasveta [241]
X is girl, and y is boy, they are formed by fission.
6 0
3 years ago
Read 2 more answers
TILEF
torisob [31]

Answer:

Na

Explanation:

sodium has mass number 23 and atomic number 11 so number of protons =number of electrons =atomic number which is 11 and number of neutrons=mass number-number of protons =23-11=12

7 0
3 years ago
The standard entropy of liquid methanol at 298K is 126.8 J/K-mol and its heat capacity is 81.6 J/K-mol. Methanol boils at 337K w
USPshnik [31]

Explanation:

First, we will calculate the entropies as follow.

 \Delta S_{2} = C_{p_{2}} ln \frac{T_{2}}{T_{1}} J/K mol

As,   T_{1} = 298 K,         T_{2} = 373.8 K

Putting the given values into the above formula we get,

     \Delta S_{2} = C_{p_{2}} ln \frac{T_{2}}{T_{1}} J/K mol

                 = 81.6 ln (\frac{373.8}{298})

                 = 18.5 J/K mol

Now,

       \Delta S_{3} = \frac{\Delta H_{vap}}{T_{b.p}}

                  = \frac{35270 J}{373.8}

                  = 94.2 J/mol K

Also,

    \Delta S_{4} = C_{p_{4}} ln \frac{T_{2}}{T_{1}}

                = 43.89 \times ln (\frac{800}{373.8})

                = 33.4 J/K mol

Now, we will calculate the entropy of one mole of methanol vapor at 800 K as follows.

   \Delta S_{T} = \Delta S^{o}_{1} + \Delta S_{2} + \Delta S_{3} + \Delta S_{4}

                 = (126.8 + 18.5 + 94.2 + 33.4) J/K mol

                 = 272.9 J/K mol

Thus, we can conclude that the entropy of one mole of methanol vapor at 800 K is 272.9 J/K mol.

7 0
3 years ago
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