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Alika [10]
3 years ago
14

It's science pls help ​

Chemistry
1 answer:
GREYUIT [131]3 years ago
3 0

Answer:

1.5

Explanation:

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A 100 gram block is placed on a scale that is known to have a 12% error. What will the scale read?
sesenic [268]

The scale will read <u>112 grams.</u>

Why?

Since we already know the percent error of the scale (12%) and we also know the mass of the block that is placed on the scale, we can calculate what will be the read of the scale by using the following formula:

ScaleRead=100g+(100g*\frac{12}{100})=100g+(100g*0.12)=100g+12g\\\\ScaleRead=112g

We can see that the scale will read 112 grams.

Let's verify that we are right by using the following formula to verify if the obtained value for the scale read will be 12%:

PercentError=\frac{ActualValue-RealValue}{RealValue}*100=\frac{112g-100g}{100g}*100\\\\PercentError=\frac{12g}{100g}*100=0.12*100=12(percent)

Hence, we can see that the scale will read <u>112 grams.</u>

Have a nice day!

7 0
4 years ago
The chemical formula for lithium fluoride is lif . a chemist determined by measurements that 0.035 moles of lithium fluoride par
Mnenie [13.5K]
Answer:
mass = 0.907865 grams

Explanation:
From the periodic table:
molar mass of Li = 6.941 grams
molar mass of F = 18.998 grams
Therefore:
molar mass of LiF = 6.941 + 18.998 = 25.939 grams/mole

number of moles can be calculated as follows:
number of moles = mass / molar mass
We have:
number of moles = 0.035 moles
molar mass = 25.939 grams/mole

Substitute in the equation to get the mass as follows:
0.035 = mass / 25.939
mass = 0.035 * 25.939 = 0.907865 grams

Hope this helps :)
3 0
3 years ago
Is it necessary that compounds be colored to be separated by chromatography?
blondinia [14]
No itt is not required
4 0
3 years ago
Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.
Maksim231197 [3]

The theoretical yield of SnS_2 will be 4.20 grams while the percent yield will be 7.93%

<h3>How is yield calculated?</h3>

From the equation of the reaction, the mole ratio of SnBr_4 to Na_2S is 1:2.

Mole of 48.1 mL, 0.478 M  SnBr_4 = 0.478 x 48.1/100 = 0.023 mols

Mole of 48.8 mL, 0.160 M   Na_2S = 0.160 x 48.8/1000 = 0.0078 moles

SnBr_4Na_2S is the limiting reactant.

Mole ratio of  SnBr_4  and SnS_2 = 1:1

Equivalent mole of  SnS_2 = 0.023 moles

Mass of 0.023 noles SnS_2= 0.023 x 182.81 = 4.20 grams

With 0.0333 g of SnS_2 recovered, percent yield = 0.333/4.2 x 100 = 7.93%

More on yields of reactions can be found here: brainly.com/question/17042787

#SPJ1

Tin(IV) sulfide, SnS2, a yellow pigment, can be produced using the following reaction.

SnBr4(aq)+2Na2S(aq)⟶4NaBr(aq)+SnS2(s)

Suppose a student adds 48.1 mL of a 0.478 M solution of SnBr4 to 48.8 mL of a 0.160 M solution of Na2S.

1) Calculate the theoretical yield of SnS2. ;

2) The student recovers 0.333 g of SnS2. Calculate the percent yield of SnS2 that the student obtained.

7 0
2 years ago
An 80.0 g sample of iodine-131 was placed in a sealed vessel forty days ago. Only 2.5 g of this isotope is now left. What is its
MA_775_DIABLO [31]
1.25, you divide 2.5 by 80, then times by 40
3 0
3 years ago
Read 2 more answers
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