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Pepsi [2]
1 year ago
7

1. Most of an atom is empty space, except for a tiny, dense core called the ___.

Chemistry
1 answer:
zhenek [66]1 year ago
3 0

Answer:

Nucleus

Protons and neutrons

elements

periods

groups

Explanation:

Can I have brainliest?

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The concentration of a biomolecule inside a rod-shaped prokaryotic cell is 0.0029 m. calculate the number of molecules inside th
bagirrra123 [75]
Molarity is expressed as:
Molarity = moles / liter

Given that the cell is rod-shaped, its volume is calculated using the formula for a cylinder's volume:

V = πr²L
V = π * (0.6)² * 4.9
V = 5.54 μm³

1 Liter = 10³ mm³
1 mm = 10³ μm
1 mm³ = 10⁹ μm³
1 liter = 10¹² μm³

So the volume in liters is:
5.54 x 10⁻¹² L

Moles = molarity * liters
Moles = 0.0029 * 5.54 x 10⁻¹²
Moles = 1.61 x 10⁻¹⁴

To get the number of molecules, we multiply the moles by Avagadro's number

Number of molecules = 1.61 x 10⁻¹⁴ * 6.02 x 10²³

There are 9.69 x 10⁹ molecules in the cell
4 0
3 years ago
What is the Ground state electron configuration for lead?
notsponge [240]

Answer:

Lead atoms have 82 electrons and the shell structure is 2.8. 18.32. 18.4.

Explanation:

The ground state electron configuration of ground state gaseous neutral lead is [Xe].

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3 years ago
scandium47 has a half-life of 35s. suppose you have a 45g sample of scadium 47 how much of the sample remains unchanged after 14
Mars2501 [29]

 The much  of the sample that would remain  unchanged  after 140 seconds is 2.813 g

Explanation

Half life  is time taken for the quantity  to reduce  to half its original value.

if the half life  for Scandium  is 35 sec, then the number  of half life in 140 seconds

=140 sec/ 35 s = 4 half life

Therefore 45 g after first half life = 45 x1/2 =22.5 g

               22.5 g after second half life = 22.5 x 1/2 =11.25 g

            11.25 g after third half life = 11.25 x 1/2 = 5.625 g

             5.625 after  fourth half life = 5.625 x 1/2 = 2.813

therefore 2.813 g  of Scandium 47 remains  unchanged.

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