Answer:
A. maintain electrical neutrality in the half-cells via migration of ions
Explanation:
Salt bridge -
For an electrochemical reaction , involving an anode and a cathode , both the electrodes are connect via a salt bridge to complete the circuit for the reaction .
One of the very important use of a salt bridge is to maintain the electrical neutrality of the respective half cells , which is achieved by the movement of ions .
Hence , from the given options , the correct option is ( a ) .
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Answer:
The correct answer is -
Prokaryotic unicellular -
Eubacteria - is the domain of unicellular organisms that has a prokaryotic cell
Archaebacteria - is one of the two domains of the prokaryotic organisms that are unicellular.
Eukaryotic multicellular (autotroph) -
Plantae - is the multicellular kingdom of the eukaryotic cells and as they produce their own food by photosynthesis called autotrophs.
protists - the autotrophic protists that are multicellular comes under algae, especially red algae.
Eukaryotic multicellular (heterotroph) -
Animalia - The Animalia kingdom is the kingdom of the heterotrophic eukaryotic organism that mostly has multicellular bodies. They depend on plants or other animals for their food.
Fungi - are mostly heterotrophic eukaryotic as they get their nutrient from other organisms are mostly multicellular.
Protist - some protists are heterotrophic as well.
Eukaryotic multicellular/unicellular (heterotroph/autotroph) -
Plantae
protists
Animalia
Fungi
Answer:
-241 kJ/mol
Explanation:
Let's consider the reaction of hydrogen with excess oxygen to form water.
2 H₂ + O₂ ⟶ 2 H₂O
When 2.16g of hydrogen reacts with excess oxygen, 258 kJ of heat are released, that is, Q = -258 kJ. Considering that the molar mass of hydrogen is 2.02 g/mol, the change of enthalpy associated with the reaction of 1.00 mol of hydrogen gas is:
ΔH° = -258 kJ/2.16 g × (2.02 g/1.00 mol) = -241 kJ/mol