Answer:
ΔG = 16.218 KJ/mol
Explanation:
- dihydroxyacetone phosphate ↔ glyceraldehyde-3-phosphate
∴ ΔG° = 7.53 KJ/mol * ( 1000 J / KJ ) = 7530 J/mol
∴ R = 8.314 J/K.mol
∴ T = 298 K
∴ Q = [glyceraldehyde-3-phosphate] / [dihydroxyacetone phosphate]
⇒ Q = 0.00300 / 0.100 = 0.03
⇒ ΔG = 7530J/mol - (( 8.314 J/K.mol) * ( 298 K ) * Ln ( 0.03 ))
⇒ ΔG = 16217.7496 J/mol ( 16.218 KJ/mol )
Answer:most of the positively charge particles should be bounce back at a range of angles as they collide with the atoms in the foil; only a few should pass straight through the foil
Explanation:
Answer:
Here are a few more examples:
Smoke and fog (Smog)
Dirt and water (Mud)
Sand, water and gravel (Cement)
Water and salt (Sea water)
Potassium nitrate, sulfur, and carbon (Gunpowder)
Oxygen and water (Sea foam)
Petroleum, hydrocarbons, and fuel additives (Gasoline)
Heterogeneous mixtures possess different properties and compositions in various parts i.e. the properties are not uniform throughout the mixture.
Examples of Heterogeneous mixtures – air, oil, and water, etc.
Examples of Homogeneous mixtures – alloys, salt, and water, alcohol in water, etc.
Explanation:
Answer:
The final pressure is 90.1 atm.
Explanation:
Assuming constant temperature, we can solve this problem by using <em>Boyle's Law</em>, which states:
Where in this case:
We <u>input the given data</u>:
- 159 atm * 463 L = P₂ * 817 L
And <u>solve for P₂</u>:
The final pressure is 90.1 atm.
Answer:
To obtain the grams of fat that the ground round has, knowing that it weighs 1.33 pounds we must pass this value to grams. Since 1 pound equals 453.59 grams, 1.33 pounds equals 603.27 (453.59 x 1.33).
Now, to obtain 29 percent of 603.27, we must make the following calculation: 603.27 / 100 x 29, which gives a total of 174.94 grams.
In this way, your reasoning is correct and it is probably a mistake in the book.
