1. (7 , 0) and (11 , 3) → B and D
substitute each coordinate point into the left side of the equation and if equal to 21 then it is a solution.
( 7 , 0) → (3 × 7) - ( 4× 0) = 21 - 0 = 21
(11 , 3) → (3 × 11 ) - ( 4 × 3) = 33 - 12 = 21
2. ( 2 , - 9 ) is a solution to the equation
substitute the coordinates into the equation and if equal to 13 the it is the solution.
(2 , - 9 ) → (5 × 2 ) - (-9)/3 = 10 + 9/3 = 10 + 3 = 13
(3 , - 6) → (5 × 3) - (- 6)/3 = 15 + 6/3 = 15 + 2 = 17
thus (2 , -9 ) is the solution
4. x- intercept = (- 45 , 0)
to find the x- intercept let y = 0
1/3 x + 0 = - 15
1/3x = - 15
multiply both sides by 3
x = 3 × - 15 = - 45
thus x -intercept = ( - 45 , 0)
Answer:
-6re−r [sin(6θ) - cos(6θ)]
Step-by-step explanation:
the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ
x = e−r sin(6θ), y = er cos(6θ)
δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)
δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)
∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ
= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]
= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))
= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]
= -6re−r [sin(6θ) - cos(6θ)] since [cos²(6θ) + sin²(6θ)] = 1
Hello! Hopefully I will be able to clarify and answer your equation in a way that can help you understand better. Here are the steps...
N + 6/-4 = 10
N + 6 = -40
N = -40 - 6
N= -46
Hope this helped!
Answer:
0.037
Step-by-step explanation:
If the hitter makes an out 72% of the time, then the probabilty that he makes hit in 1 at-bat is 
and the probabilty that he doesn't make hit in 1 at-bat is 
The probability that the hitter makes 10 outs in 10 consecutive at-bats, assuming at-bats are independent events is
