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3 years ago

Which most likely could cause acceleration? Check all that apply.

Physics

1 answer:

Lerok [7]3 years ago

5 0

<u>Answer </u>

Wind

Water movement

A hill

<u>Explanation. </u>

The question does not specify it is the acceleration of what is to be accelerated. So my answer will be general. Acceleration is the change of velocity with time.

Wind can cause acceleration of sound. If the sound is travelling in the direction of sound, its speed wound increase. The reverse is also true.

Water movement can also cause acceleration. When a bout is moving in the direction of water movement, then it will be expected that the resultant speed of the bout to be higher. If the bout was moving against the water movement, its speed would be decreased.

A hill would reduce the speed of a moving vehicle. This is also an acceleration that is negative (deceleration).

A stop light and a flat road cannot cause acceleration.

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If the velocity of a pitched ball has a magnitude of 47.0 m/s and the batted ball's velocity is 55.0 m/s in the opposite directi

Naddik [55]

Answer:

14.79 kgm/s

Explanation:

Data provided in the question

Let us assume the mass of baseball = m = 0.145 kg

The Initial velocity of pitched ball = $v_i$ = 47 m/s

Final velocity of batted ball in the opposite direction = $v_f$ = -55m/s

Based on the above information, the change in momentum is

$\Delta P = m(v_f -v_i)$

$= 0.145 kg(-55m/s - 47m/s)$

= 14.79 kgm/s

Hence, the magnitude of the change in momentum of the ball is 14.79 kg m/s

3 0

3 years ago

A flat, 181 ‑turn, current‑carrying loop is immersed in a uniform magnetic field. The area of the loop is 4.97 cm2 and the angle

Sidana [21]

Answer:

B = 0.135T

Explanation:

To find the magnitude of the magnetic field you use the following formula, for the torque produced by a magnetic field B in a loop:

$\tau=NIABsin\theta$ (1)

τ: torque = 1.51*10^-5 Nm

I: current = 2.47mA = 2.47*10^-3 A

B: magnitude of the magnetic field

A: area of the loop = 4.97cm^2 = 4.97(10^-2m)^2=4.97*10^-4m^2

N: turns = 181

θ: angle between B and the magnetic dipole (same as the direction of the normal to the plane)

You replace the values of the parameters in (1). Furthermore you do B the subject of the formula:

$B=\frac{\tau}{NIAsin\tetha}=\frac{1.51*10^{-5}Nm}{(181)(2.47*10^{-3}A)(4.97*10^{-4}m^2)(sin30.1\°)}=0.135T$

3 0

3 years ago

Which best describes accuracy?

Likurg_2 [28]

The answer is either c or b

7 0

3 years ago

Read 2 more answers

HURRY!!!!! Which change of state is shown into the model?

nadezda [96]

Option (B) is correct. The process shown in the model is the process of DEPOSITION.

Explanation:

The first container shows the molecules of the substance present inside it at a fairly large distance from one another whereas the second container, the molecules of the substance are very close to each other.

This shows that the substance in the first container is gaseous in nature whereas the substance in the second container is solid in nature as its molecules are closely packed.

Therefore, it shows the phase transition of a substance from gaseous sate to the solid state. The process of conversion of a gas directly into a solid is termed as deposition. This process is the opposite of the Sublimation in which the solid gets directly converted into a gas. Thus, the process is also termed as desublimation.

Thus, Option (B) is correct. The process shown in the model is the process of DEPOSITION.

Learn More:

1. Kinetic energy of a body depends on brainly.com/question/137098

2. X-component of the object's acceleration brainly.com/question/7114558

3. Velocity is a combination of which of the following brainly.com/question/1890447

Answer Details:

Grade: High School

Subject: Physics

Chapter: States of matter

Keywords:

Sublimation, phase transition, solid, gas, molecules, distance, deposition, freezing, boiling, container, second.

7 0

4 years ago

A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 50.4 m/s and returns the shot with the ball

lora16 [44]

Explanation:

It is given that,

Mass of the ball, m = 0.06 kg

Initial speed of the ball, u = 50.4 m/s

Final speed of the ball, v = -37 m/s (As it returns)

(a) Let J is the magnitude of the impulse delivered to the ball by the racket. It can be calculated as the change in momentum as :

$J=m(v-u)$

$J=0.06\times (-37-(50.4))$

J = -5.24 kg-m/s

(b) Let W is the work done by the racket on the ball. It can be calculated as the change in kinetic energy of the object.

$W=\dfrac{1}{2}m(v^2-u^2)$

$W=\dfrac{1}{2}\times 0.06\times ((-37)^2-(50.4)^2)$

W = -35.1348 Joules

Hence, this is the required solution.

6 0

4 years ago