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wlad13 [49]
3 years ago
5

wo ladybugs of the same mass are on a record that is on a record player. The record player is turned on and it reaches a constan

t velocity. show answer No Attempt If the male ladybug is all the way at the edge and the female ladybug is halfway between the center and the edge, what can be said about their moments of inertia?
Physics
1 answer:
coldgirl [10]3 years ago
8 0

Answer:

The moment of inertia of the male ladybug is 4 times the moment of inertia of the female ladybug.

Explanation:

The moment of inertia of a single-point object rotating about an axis is given by

I=mr^2

where

m is the mass of the object

r is the distance of the object from the axis of rotation

In this problem, we have:

- The mass of the two ladybugs is the same, m_M=m_F

- The distance of the male ladybug from the axis of rotation is twice that of the female ladybug, r_M=2r_F

So, the moment of inertia of the female ladybug is

I_F=m_F r_F^2

While the moment of inertia of the male ladybug is

I_M = m_M r_M^2 = m_F (2r_F)^2=4 m_F r_F^2=4I_F

Therefore, the moment of inertia of the male ladybug is 4 times the moment of inertia of the female ladybug.

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. Each valve A, B, and C, when open, releases water into a tank at its own constant rate. With all three valves open, the tank f
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Answer:

Time taken by A and B is 1.2 hr.

Explanation:

Given that

Time taken by tank when all(A+B+C) are open = 1 hr

Time taken by tank when A+C are open = 1.5 hr

Time taken by tank when B+C are open = 2 hr

If we treat as filling of tank is a work then

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1 = 1(1/a+1/b+1/c)          ---------1

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1 = 2(1/b+1/c)             --------3

From equation 1 and 3

1=1(1/a+1/2)

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Form equation 2

1 = 1.5(1/2+1/c)

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From equation 3

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b=3

So time taken by

A is alone to fill tank is 2 hr

B is alone to fill tank is 3 hr

C is alone to fill tank is 6 hr

So time\ taken\ by\ A\ and\ B =\dfrac{2\times 3}{2+3} hr

Time taken by A and B is 1.2 hr.

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