Answer:
The moment of inertia of the male ladybug is 4 times the moment of inertia of the female ladybug.
Explanation:
The moment of inertia of a single-point object rotating about an axis is given by
![I=mr^2](https://tex.z-dn.net/?f=I%3Dmr%5E2)
where
m is the mass of the object
r is the distance of the object from the axis of rotation
In this problem, we have:
- The mass of the two ladybugs is the same, ![m_M=m_F](https://tex.z-dn.net/?f=m_M%3Dm_F)
- The distance of the male ladybug from the axis of rotation is twice that of the female ladybug, ![r_M=2r_F](https://tex.z-dn.net/?f=r_M%3D2r_F)
So, the moment of inertia of the female ladybug is
![I_F=m_F r_F^2](https://tex.z-dn.net/?f=I_F%3Dm_F%20r_F%5E2)
While the moment of inertia of the male ladybug is
![I_M = m_M r_M^2 = m_F (2r_F)^2=4 m_F r_F^2=4I_F](https://tex.z-dn.net/?f=I_M%20%3D%20m_M%20r_M%5E2%20%3D%20m_F%20%282r_F%29%5E2%3D4%20m_F%20r_F%5E2%3D4I_F)
Therefore, the moment of inertia of the male ladybug is 4 times the moment of inertia of the female ladybug.