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wlad13 [49]
3 years ago
5

wo ladybugs of the same mass are on a record that is on a record player. The record player is turned on and it reaches a constan

t velocity. show answer No Attempt If the male ladybug is all the way at the edge and the female ladybug is halfway between the center and the edge, what can be said about their moments of inertia?
Physics
1 answer:
coldgirl [10]3 years ago
8 0

Answer:

The moment of inertia of the male ladybug is 4 times the moment of inertia of the female ladybug.

Explanation:

The moment of inertia of a single-point object rotating about an axis is given by

I=mr^2

where

m is the mass of the object

r is the distance of the object from the axis of rotation

In this problem, we have:

- The mass of the two ladybugs is the same, m_M=m_F

- The distance of the male ladybug from the axis of rotation is twice that of the female ladybug, r_M=2r_F

So, the moment of inertia of the female ladybug is

I_F=m_F r_F^2

While the moment of inertia of the male ladybug is

I_M = m_M r_M^2 = m_F (2r_F)^2=4 m_F r_F^2=4I_F

Therefore, the moment of inertia of the male ladybug is 4 times the moment of inertia of the female ladybug.

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Pavel [41]

Answer: it's under explanation

Explanation:Groundwater contamination occurs when man-made products such as gasoline, oil, road salts and chemicals get into the groundwater and cause it to become unsafe and unfit for human use. Materials from the land's surface can move through the soil and end up in the groundwater.

3 0
3 years ago
Does a car have antennae? what senses does it have
Ilia_Sergeevich [38]

Answer:

Explained below.

Explanation:

Yes cars have antennas.

Now there could be an antenna for listening to radio stations which could be regular radio stations or even satellite radio stations.

Also, there could be antennas used for GPS navigation or some form of communication with other vehicles that possess that type of antenna.

4 0
3 years ago
If you could go a year into the future, or 3 seconds into the past, where would you go? What date? I would go to June 6th, 2018
vova2212 [387]
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8 0
3 years ago
In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a fur
Margaret [11]

Answer:

D = -4/7 = - 0.57

C = 17/7 = 2.43

Explanation:

We have the following two equations:

3C + 4D = 5\ --------------- eqn (1)\\2C + 5D = 2\ --------------- eqn (2)

First, we isolate C from equation (2):

2C + 5D = 2\\2C = 2 - 5D\\C = \frac{2 - 5D}{2}\ -------------- eqn(3)

using this value of C from equation (3) in equation (1):

3(\frac{2-5D}{2}) + 4D = 5\\\\\frac{6-15D}{2} + 4D = 5\\\\\frac{6-15D+8D}{2} = 5\\\\6-7D = (5)(2)\\7D = 6-10\\\\D = -\frac{4}{7}

<u>D = - 0.57</u>

Put this value in equation (3), we get:

C = \frac{2-(5)(\frac{-4}{7} )}{2}\\\\C = \frac{\frac{14+20}{7}}{2}\\\\C = \frac{34}{(7)(2)}\\\\C =  \frac{17}{7}\\

<u>C = 2.43</u>

5 0
3 years ago
HELP PLEASE!!
aliya0001 [1]

Answer:

m=41 kg

v=0,02 ms

R=2,1 m

F-?

a=v²/R

a=(0,02) ²/2,1=0,0002

F=m*a

F=41*0,0002=0,0082 H

F=0,0082 H

3 0
3 years ago
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