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2 years ago

determine whether the aqueous solutions of each of the following salts will be acidic, basic, or neutral

Chemistry

1 answer:

eduard2 years ago

6 0

KCl is neutral because KOH is a strong base and HCl is a strong acid

To determine if the salt is neutral, acidic or basic, determine how the salt was made, or from which acid and base it was derived. Once we have determined how the salt was made, determine if the acid and base are both strong, weak or one of each. If both are strong (e.g. NaOH + HCl), then the salt (NaCl) is NEUTRAL. If the base is strong and the acid is weak (KOH + HCN), then the salt (KCN) is BASIC. IF the base is weak and the acid is strong (NH3 + HCl), then the salt (NH4Cl) is ACIDIC. If both the base and the acid are weak (NH3 + CH3COOH), then then salt (CH3COONH4) will have a pH determined by which is stronger (the acid or the base) and this will depend on the Ka of the weak acid compared to the Kb of the weak base.

KCl is neutral because KOH is a strong base and HCl is a strong acid NaCN is generally basic because NaOH is a strong base and HCN is a very week acid. NH4NO3 is usually acid because HNO3 is a strong acid and NH4OH is a week base

CH3COONH4 is exactly neutral because both NH4OH ad CH3COOH are respectively week base and week acid. Moreover, the Ka of acetic acid is exactly equal to the Kb of NH4OH

To know about strong base.

brainly.com/question/16749233

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One molecule of the spherically shaped, oxygen‑carrying protein in red blood cells, hemoglobin, has a diameter of 5.5 nm 5.5 nm

horrorfan [7]

Answer : The diameter in meters is, $5.5\times 10^{-9}m$

Explanation :

As we are given that the diameter of red blood cells is, 5.5 nm. Now we have to convert it into meter.

The conversion used from nanometer to meter is:

$1nm=10^{-9}m$

As, $1nm=10^{-9}m$

So, $5.5nm=\frac{5.5nm}{1nm}\times 10^{-9}m=5.5\times 10^{-9}m$

Thus, the diameter in meters is, $5.5\times 10^{-9}m$

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3 years ago

When hafnium metal is heated in an atmosphere of chlorine gas, the product of the reaction is found to contain 62.2 percent Hf b

Artemon [7]

Answer:

HfCl3

Explanation:

Step 1

Divide the percent by mass of each element by its relative atomic mass

Hf- 62.2/178.5, Cl-37.4/35.5

0.348, 1.054

Step2

Divide through by the lowest ratio

0.348/0.348, 1.054/0.348

1, 3

Therefore the empirical formula is HfCl3

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3 years ago

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ahrayia [7]

Answer:

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Explanation:

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3 years ago

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tino4ka555 [31]

Answer:

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3 years ago