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Lyrx [107]
1 year ago
14

48w + 42x. Write you're answere as a product with a whole number greater than 1???

Mathematics
2 answers:
JulsSmile [24]1 year ago
8 0
6(8w+7x) that is the answer
Natali [406]1 year ago
4 0

Answer:

6(8w + 7x)

Step-by-step explanation:

Hello!

The greatest common factor between 48 and 42 is 6. We can factor out 6 from each term.

<h3>Factor</h3>
  • 48w + 42x
  • 6(8w) + 6(7x)
  • 6(8w + 7x)

The expression is 6(8w + 7x).

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Shades R Us charges $20 per day to rent a lounge chair and $15 per day to rent an umbrella. Dan and Lisa paid a total of $245 to
goblinko [34]

Answer:

$151.88 costs to Dan algebraic form

$245/2 = $122.50+20+15 = 157.5 is the answer though.

Step-by-step explanation:

35x+20(x-1)

35x + (20x -1)

35x +20x -1

35x -20x-20

x= 53/11

53/11 = 4.81

4.81 x 20 = $96.20 on chairs

4.81 x 15 = 72.15 on umbrella

96+72 = 168.35

245-168.35 = 76.65

76.65 + 20 = 96.65

Because we subtracted to get 168.35 we have the difference of $15 which is the difference of what he and she paid we half this amount = $7.50 half the 0.45 additional found on Dans $96.65 = $0.22 and find $7.72 balance to add to his 96.20

Added together his costs out of 245 was $104.37+ 76.65 = $181.20

Costs of umbrella = 76.65/2 = 39.325

181.20 -29.325=151.87 rounded up to 151.87

As x = 53/11 the decimal of this is 4.81 = x

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3 years ago
Which of the following is a logarithmic function?
Art [367]

Answer:

c

Step-by-step explanation:

6 0
3 years ago
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Which is likely to have a mass close to 700 grams?
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50 points! Answer AS much as you can, I give Brainliest!
olga_2 [115]

Answer:

9.  y = 8

10.  n = 21

11.  44 = v

12.  c = 35

Step-by-step explanation:

9.   9y = 72

Divide each side by 9

9y/9 = 72/9

y = 8

10.  3n = 63

Divide each side by 3

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11.  4 = v/11

Multiply each side by 11

4*11 = v/11*11

44 = v

12.  c/7 = 5

Multiply each side by 7

c/7*7 = 5*7

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3 years ago
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Drag these fractions to put them from greatest to least 1/4, 1/5, 1/8, 1/10
const2013 [10]
Its in that exact order haha

greatest to least:
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