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Aleksandr [31]
3 years ago
12

Which set of numbers gives the correct possible values of I for n = 3?

Chemistry
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:

0 1 2 3

Explanation:

L=0 1 2 3....(n-1)

determine the shape of atomic orbitals

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Suppose you have a system made up of water only, with the container and everything beyond being the surroundings. Consider a pro
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Yes

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The possibility of evaporating and condensing is a proof of reversible reaction

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Water is separated into oxygen gas (o2) and hydrogen gas (h2) using a process called electrolysis. after electrolysis, 0.15 mole
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Volume of 1 mole of any gas under STP = 22.4 L,
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7 0
3 years ago
Rory answered that absolute zero is 0°K. Is this answer correct? Explain why or why not.
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Yes, this answer is correct.

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3 years ago
If 28.0 grams of Pb(NO3)2 react with 18.0 grams of NaI, what mass of PbI2 can be produced? Pb(NO3)2 + NaI → PbI2 + NaNO3
ss7ja [257]

Answer:- 27.7 grams of PbI_2 are produced.

Solution:- The balanced equation is:

Pb(NO_3)_2+2NaI\rightarrow PbI_2+2NaNO_3

let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.

Molar mass of Pb(NO_3)_2 = 207.2+2(14.01)+6(16)  = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2 = 207.2+2(126.90) = 461 gram per mol

let's do the calculations for the grams of the product for the given grams of each of the reactant:

28.0gPb(NO_3)_2(\frac{1molPb(NO_3)_2}{331.22gPb(NO_3)_2})(\frac{1molPbI_2}{1molPb(NO_3)_2})(\frac{461gPbI_2}{1molPbI_2})

= 39.0gPbI_2

18.0gNaI(\frac{1molNaI}{149.89gNaI})(\frac{1molPbI_2}{2molNaI})(\frac{461gPbI_2}{1molPbI_2})

= 27.7gPbI_2

From above calculations, NaI gives least amount of PbI_2, so the answer is, 27.7 g of PbI_2 are produced.

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