Mars has a very thin atmosphere, and yet its surface temperatures are higher than would be expected, given its distance from the
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Answer:
minimum initial velocity is 21.35 m/s
Explanation:
given data
distance S = 30 m
height h = 30 m
maximum acceleration a = 2 m/s²
to find out
minimum initial velocity that your friend could have thrown the object to enable you to catch
solution
first we get here time with the help of second equation of motion
time = ..................1
put her value we get
time =
time = 5.477 second
and that is time which tossed object must be take so we apply here again second equation of motion that is
-S = ut - 0.5 × gt² .......................2
-30 = u× 5.477 - 0.5 ×9.8×5.477²
solve it we get
u = 21.35 m/s
so minimum initial velocity is 21.35 m/s
The potential energy of the object is 78.4 J
Explanation:
The gravitational potential energy (GPE) of an object is the energy possessed by the object due to its position in a gravitational field.
For an object near the Earth's surface, the GPE is given by:
where
m is the mass of the object
is the acceleration of gravity near the Earth's surface
h is the height of the object relative to the surface
For the object in this problem,
m = 2 kg
h = 4 m
Substituting, we find its GPE:
Learn more about potential energy:
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