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3 years ago

A neutral atom has no overall charge. Explain this in terms of its particles.

Physics

2 answers:

vagabundo [1.1K]3 years ago

6 0

Answer:

ffsggerv

Explanation:

sdgsdv

ruslelena [56]3 years ago

4 0

Answer:

i just need points rn sorry

Explanation:

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Can someone help me with this??

fenix001 [56]

Answer:

Explanation:

Have a nice day :)

5 0

3 years ago

A cat rides a merry-go-round while turning with uniform circular motion. At time t1 = 2.00 s, the cat's velocity is v with arrow

goldenfox [79]

Answer:

Part a)

$a_c = 2.07 m/s^2$

Part b)

$a_{avg} = 1.32 m/s^2$

Explanation:

As we know that it makes half revolution in given time interval

so we have

$\frac{T}{2} = t_2 - t_1$

$\frac{T}{2} = 9 - 2$

$T = 14 s$

now the angular speed is given as

$\omega = \frac{2\pi}{T}$

$\omega = \frac{2\pi}{14}$

$\omega = 0.448 rad/s$

now linear speed is given as

$v = \sqrt{2.30^2 + 4.00^2}$

$v = 4.61 m/s$

now we have

$v = R \omega$

$4.61 = R(0.448)$

$R = 10.3 m$

Now centripetal acceleration is given as

$a_c = \omega^2 R$

$a_c = 0.448^2 \times 10.3$

$a_c = 2.07 m/s^2$

Part b)

Average acceleration of the cat is given as

$a_{avg} = \frac{v_2 - v_1}{\Delta t}$

$a_{avg} = \frac{2v}{\Delta t}$

$a_{avg} = \frac{2(4.61)}{9 - 2}$

$a_{avg} = 1.32 m/s^2$

7 0

4 years ago

What is the si unit of power?

grandymaker [24]

The SI unit of power is the watt, which is equal to one joule/per second.

So I would say Watt is the answer. Hope it helped. :)

6 0

4 years ago

Read 2 more answers

A car traveling at 30 m/s runs out of gas while traveling up a 10 slope. how far up the hill what coast before starting to roll

kaheart [24]

Answer:

264.7 m

Explanation:

The net force felt by the car travelling along the slope is equal to the component of the weight parallel to the slope, so:

$F=-mg sin \theta$

where

m is the mass of the car

g = 9.8 m/s^2 is the acceleration of gravity

$\theta=10^{\circ}$

and the negative sign is due to the fact the force is opposite direction to the motion of the car

The acceleration of the car is therefore:

$a=\frac{F}{m}=-gsin \theta=-9.8 sin 10^{\circ}=-1.7 m/s^2$

Now we can find how far the car went up the hill by using the equation:

$v^2-u^2 = 2ad$

where

v = 0 is the final velocity of the car

u = 30 m/s is the initial velocity

g = -1.7 m/s^2 is the acceleration

d is the distance covered

Solving for d,

$d=\frac{v^2-u^2}{2a}=\frac{0-30^2}{2(-1.7)}=264.7 m$

3 0

4 years ago

A plane leaves the airport in Galisteo and flies 160 km at 66.0 ∘ east of north; then it changes direction to fly 260 km at 49.0

user100 [1]

The question doesn't have any particular requirement, but we'll compute the displacement of the plane from its initial and final landing point in the pasture

Answer:

$\displaystyle |\vec{r}|=321.464\ km$

$\displaystyle \theta =-19.395^o$

Explanation:

Displacement

The vector displacement $\vec r$ is a measure of the change of position of a moving object. The displacement doesn't depend on the path followed, only on the final and initial positions. Its scalar counterpart, the distance, does measure the total space traveled and considers all the changes in the direction taken by the object. To find the displacement, we must add all the particular displacements by using vectors.

The plane first flies 160 km at 66° east of north. To find the vector expression of this displacement, we must know the angle with respect to the East direction or North of East. Knowing the angle East of North is 66°, the required angle is 90°-66°=34°

The first vector is expressed as

$\displaystyle \vec{r_1}=\left \langle 160^o\ cos34^o, 160\ sin34^o \right \rangle$