PLEASE HELP!!

Physics

1 answer:

defon3 years ago

7 0

The right answer is A

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WARRIOR [948]

Here is the answer of a tutor

Take a look.

$\sqrt[2]{24+5}$

8 0

1 year ago

A batter hits two baseballs with the same force.One hits the ground near third base.The other is a home run out of the park.Wher

andrezito [222]

The formula for work is:

W = F * d Where W is work, F is Force, and d is distance.

Without doing any math, it can be seen from the equation that work is directly proportional to the force applied and the distance it travels. The homerun hit both traveled more distance and had a grater force applied to it in order to achieve this distance (assuming both baseballs weighed the same). Based on this reasoning, it is valid to conclude that the baseball which was a homerun was the hit that accomplished more work.

5 0

3 years ago

3. Write the numbers given below in scientific notation.

KIM [24]

Answer:
a) 3 * 10^9 ms
b) 1.6 * 10^-9 gm
c) 6.4 * 10^6 m
d) 5.48 * 10^5 s
Explanation:
Scientific notation is always written in [number from 0-10] (multiplied by) [10] raised to the power 'n'

4 0

2 years ago

The gravitational acceleration on Mars is 3.71 m/s2. If the pendulums were set in motion on the red planet, how would that affec

Elanso [62]

On Earth, the period of a pendulum is given by:
$T_{earth}=2\pi \sqrt{ \frac{L}{g_{earth} }$
where L is the length of the pendulum and $g_{earth}=9.81~m/s^2$ is the gravitational acceleration on Earth.
Similarly, the period of the same pendulum on Mars will be
$T_{mars}=2\pi \sqrt{ \frac{L}{g_{mars} }$
where $g_{mars}=3.71~m/s^2$ is the gravitational acceleration on Mars.
Therefore, if we want to see how does the period of the pendulum on Mars change compared to the one on Earth, we can do the ratio between the two of them:
$\frac{T_{mars}}{T_{earth}}= \sqrt{ \frac{g_{earth}}{g_{mars}} } = \sqrt{ \frac{9.81~m/s^s}{3.71~m/s^2} }=1.63$
Therefore, the period of the pendulum on Mars will be 1.63 times the period on Earth.

6 0

4 years ago

A ufo was detected on the radar flying 7400 miles in 3 min, what is the estimated speed per hour?

Ghella [55]

S=7400mi
t=3 min= 0.05h
v=7400mi/0.05h
v=148000mph

8 0

4 years ago