Answer: The boiling point of solution is
Explanation:
Elevation in boiling point:
where,
= boiling point of solution = ?
= boiling point of toluene =
= boiling point constant of toluene =
m = molality
i = Van't Hoff factor = 1 (for non-electrolyte)
= mass of solute = 7.94 g
= mass of solvent (toluene) = 69.2 g
= molar mass of solute = 254g/mol
Now put all the given values in the above formula, we get:
Therefore, the boiling point (in °C) of a solution is 112.16
Answer:
Mass, M = 4.859 Kg
Explanation:
Given the following data;
Radius, r = 0.225 m
Moment of inertia, I = 0.123 kgm²
To find the mass;
Mathematically, the moment of inertia is given by the formula;
I = ⅖Mr²
Making M the subject of formula, we have;
Cross-multiplying, we have;
2I = Mr²
Substituting into the formula, we have;
Mass, M = 4.859 Kg
C. Both A. and B.
Explanation:
Statement A. Reducing the volume is true because of Boyle's law, which states that for a gas at fixed temperature, the pressure p and the volume V are inversely proportional:
Therefore, when the volume V is reduced, the pressure p increases.
Statement B. Adding more gas is also true: in fact, if we add gas into the container, we will have more molecules of the gas hitting the wall of the container. But the pressure of a gas is exactly given by this: by the collision of the molecules against the wall of the container, so the more the molecules of gas, the greater the pressure.
In the projectile motion, the direction is characterized by a shape of the arc. Its horizontal component travels in constant velocity while the vertical component travels in constant acceleration. The equation to be used is:
2ay = |v² - v₀²|
where
a is the acceleration due to gravity equal to 9.81 m/s²
y is the height
v is the final velocity
v₀ is the initial velocity
Substitute y=1/2*H and v = 3/4*v₀. The equation for maximum height is
H = v₀²sin²θ/2a
Thus,
(2)(9.81)(1/2)(H) = |(3/4v₀)² - v₀²|
(2)(9.81)(1/2)(v₀²sin²θ/2(9.81)) = |(3/4v₀)² - v₀²|
(1/2)v₀²sin²θ = 7/16 * v₀₂
(1/2)sin²θ = 7/16
sin θ = [2*(7/16)]² = 0.765625
θ = sin⁻¹(0.765625) = 49.96°
Therefore, the launch angle is 49.96°.
Answer:
x=?
dt=?
vi=23m/s
vf=0m/s (it stops)
d=0.25m/s^2
time =
vf=vi+d: 0=23m/s+(0.25m/s^2)t
t=92s
displacement=
vf^2=vi^2+2a(dx)
23^2=0^2+2(0.25m/s^2)x =-1058m
Explanation:
you can find time from vf = vi + a(Dt): 0 = 23 m/s + (0.25 m/s/s)t so t = 92 s and you can find the displacement from vf2 = vi2 + 2a(Dx) and find the answer in one step: 232 = 02 + 2(0.25 m/s/s)x so x = -1058 m