Question

12.5 g of water are warmed from 12C to 72C. How much energy in J were absorbed? (specific heat of water=4.18 J/gC)

Answer 1

Answer

Energy = 3135 J

Explanation

Given:

Mass of water = 12.5 g

Final temperature = 72 C

Initial temperature = 12 C

Specific heat of water = 4.18 J/g C

Required: Energy

Solution

Q = m x Cp x ΔT

where Q is heat absorbed or released

m is the mass

Cp is the specific heat capacity

ΔT = final temperature - initial temperature

Q = 12.5 g x 4.18 J/gC x (72 - 12 C)

Q = 3135 J