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Anuta_ua [19.1K]
1 year ago
14

open the phase diagram for co2 given in the introduction again. use the phase diagram for co2 in the interactive activity and de

termine which of the following statements are correct.
Chemistry
1 answer:
Annette [7]1 year ago
3 0

The phase diagram of CO2 has a melting curve that slopes up and to the right, in contrast to the phase diagram of water, which has a more conventional shape. It is impossible for liquid CO2 to exist at pressures lower than 5.11 atm because the triple point is 5.11 atm and 56.6 °C.

Due to the fact that ice is less thick than liquid water, the phase diagram of water has an odd melting point that drops with pressure. Carbon dioxide cannot exist as a liquid at atmospheric pressure, according to the phase diagram of the gas. Thus, gaseous carbon dioxide directly sublimes from solid carbon dioxide.

Learn more about solid carbon dioxide.

brainly.com/question/16894647

#SPJ4

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Bacteria can be heterotrophs or autotrophs<br> true or false?
Norma-Jean [14]

Answer:

True

Explanation:

I learned about it a few years ago

6 0
3 years ago
Predict whether a reaction occurs, and write balanced complete and net ionic equations:(a) Iron (III) chloride (aq) + cesium pho
Neporo4naja [7]

Answer : The balanced complete and net ionic equations are written below.

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a) The balanced molecular equation will be,

FeCl_3(aq)+Cs_3PO_4(aq)\rightarrow 3CsCl(aq)+FePO_4(s)

The complete ionic equation in separated aqueous solution will be,

Fe^{3+}(aq)+3Cl^{-}(aq)+3Cs^{+}(aq)+PO_4^{3-}(aq)\rightarrow 3Cs^{+}(aq)+3Cl^{-}(aq)+FePO_4(s)

In this equation the species present are, 3Cl^{-}\text{ and }Cs^{+} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Fe^{3+}(aq)+PO_4^{3-}(aq)\rightarrow FePO_4(s)

(b) The balanced molecular equation will be,

2NaOH(aq)+Cd(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+Cd(OH)_2(s)

The complete ionic equation in separated aqueous solution will be,

2Na^{+}(aq)+2OH^{-}(aq)+Cd^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^{+}(aq)+2NO_3^{-}(aq)+Cd(OH)_2(s)

In this equation the species present are, Na^{+}\text{ and }NO_3^{-} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Cd^{2+}(aq)+2OH^{-}(aq)\rightarrow Cd(OH)_2(s)

(c) The balanced molecular equation will be,

MgBr_2(aq)+2CH_3COOK(aq)\rightarrow (CH_3COO)_2Mg(aq)+2KBr(aq)

The complete ionic equation in separated aqueous solution will be,

Mg^{2+}(aq)+2Br^{-}(aq)+2K^{+}(aq)+2CH_3COO^{-}(aq)\rightarrow Mg^{2+}(aq)+2CH_3COO^{-}(aq)+2Br^{-}(aq)+2K^{+}(aq)

In this equation all the species are the spectator ions.

Thus, there is no net ionic equation.

(d) The balanced molecular equation will be,

Ag_2SO_4(aq)+BaCl_2(aq)\rightarrow 2AgCl(s)+BaSO_4(s)

The complete ionic equation in separated aqueous solution will be,

2Ag^{+}(aq)+SO_4^{2-}(aq)+Ba^{2+}(aq)+2Cl^{-}(aq)\rightarrow 2AgCl(s)+BaSO_4(s)

In this equation no species are the spectator ions.

Thus, there is no net ionic equation.

(e) The balanced molecular equation will be,

Na_2SO_4(aq)+Sr(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+SrSO_4(s)

The complete ionic equation in separated aqueous solution will be,

2Na^{+}(aq)+SO_4^{2-}(aq)+Sr^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^{+}(aq)+2NO_3^{-}(aq)+SrSO_4(s)

In this equation the species present are, Na^{+}\text{ and }NO_3^{-} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Sr^{2+}(aq)+SO_4^{2-}(aq)\rightarrow SrSO_4(s)

5 0
3 years ago
A certain substance makes up 4.8 × 10–4 percent by mass of a normal healthy human being. How many grams of that substance would
iris [78.8K]

Answer:

0.2615 g

Explanation:

Given that mass of the body = 120 lb

The conversion of lb to g is shown below as:-

1 lb = 454 g

So, 120 lb = 120*454 g = 54480 g

The substance is 4.8\times 10^{-4}\ \% of the human body

So, Mass of that substance in the body of mass 54480 g is:-

m=\frac{4.8\times 10^{-4}}{100}\times 54480\ g=0.2615\ g

<u>0.2615 g of that substance would be found in the body of a person weighing 120 lb.</u>

4 0
3 years ago
When electrons are removed from the outermost shell of a calcium atom becomes
Maslowich
When electrons are removed from the outermost shell of calcium atom, its atom becomes positively charged, with a charge of plus one.

When an electron is added to an atom, the atom becomes negatively charged, with a charge of minus one.

When these atoms become positively or negatively charged, they are known as ions. Positively charged ions are called cations and negatively charged ions are called anions.

Calcium is identified as one of the cations because it is positively charged when its electrons are removed from its outermost shell.
7 0
3 years ago
Which of these events explains the presence of the volcano?
kenny6666 [7]
I would say the answer is C

hope this helps :)
5 0
3 years ago
Read 2 more answers
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